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Connes-Chern Character for Manifolds with Boundary and ETA ...

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CONNES-CHERN CHARACTER AND <strong>ETA</strong> COCHAINS 29<br />

By carefully tracing all the signs <strong>and</strong> i–factors involved in the graded <strong>for</strong>m valued<br />

Clif<strong>for</strong>d calculus, as well as due to the various conventions, it turns out that separating<br />

(2.10) into its scalar <strong>and</strong> 1-<strong>for</strong>m parts, using [Get93a, Lem. 2.5]<br />

b 〈〈A 0 , · · · , A k 〉〉 =<br />

= b 〈A 0 , · · · , A k 〉 − i<br />

k∑<br />

j=0<br />

b 〈A 0 , · · · , A j , dt ∧ Ḋt, A j+1 , · · · , A k 〉,<br />

(2.11)<br />

one obtains Eqs. (2.6) <strong>and</strong> (2.7).<br />

However, <strong>for</strong> completeness, we will give a more direct argument in Subsection 2.2,<br />

<strong>with</strong>out using operator valued <strong>for</strong>ms. The proof below follows the lines of the st<strong>and</strong>ard<br />

proof <strong>for</strong> the JLO cocycle representing the <strong>Chern</strong> character of a θ-summable Fredholm<br />

module (cf. [JLO88], [GeSz89]).<br />

2.1. Cocycle <strong>and</strong> transgression <strong>for</strong>mulæ <strong>for</strong> the even/odd b-<strong>Chern</strong> character<br />

(<strong>with</strong>out Clif<strong>for</strong>d covariance). Recall from Remark 2.1 that <strong>for</strong> q = 0 <strong>and</strong> k even<br />

resp. q = −1 <strong>and</strong> k odd b Ch • (D) is the b-analogue of the even, resp. odd, JLO <strong>Chern</strong><br />

character. We shall relate the ungraded (q = −1) case to the graded case <strong>with</strong> q = 1.<br />

Starting <strong>with</strong> an ungraded Dirac operator D t acting on the Hilbert space H, put<br />

( )<br />

1 0<br />

˜H := H ⊕ H, α := , ˜Dt :=<br />

0 −1<br />

( )<br />

0 Dt<br />

. (2.12)<br />

D t 0<br />

Then ˜D t is odd <strong>with</strong> respect to the grading operator α <strong>and</strong> it anti-commutes <strong>with</strong><br />

E 1 :=<br />

( )<br />

0 1<br />

. (2.13)<br />

−1 0<br />

Note that<br />

˜D t = αE 1<br />

(<br />

Dt ⊗ I 2<br />

)<br />

(2.14)<br />

<strong>with</strong> I 2 being the 2 × 2 identity matrix.<br />

Proposition 2.4. Let D t be ungraded (q = −1) <strong>and</strong> let ˜D t = αE 1 (D t ⊗ I 2 ) be the<br />

associated 1–graded (q = 1) operator. Then <strong>for</strong> k odd<br />

b Ch k (˜D t ) = 1 √ π b Ch k (D t ),<br />

b /ch k−1 (˜D, ˙ ˜D t ) = 1 √ π b /ch k−1 (D t , Ḋt).<br />

(2.15)<br />

Needless to say that these <strong>for</strong>mulæ are valid as well <strong>for</strong> Ch • <strong>and</strong> /ch • .

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