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Nonlinear Equations - UFRJ

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[SEC. 9.4: THE ALPHA THEOREM 131<br />

Those will be compared to<br />

ˆβ i = β(h βγ , t i )) and ˆγ i = γ(h βγ , t i )).<br />

Induction hypothesis: β i ≤ ˆβ i and for all l ≥ 2,<br />

‖Df(X i ) † D l f(X i )‖ ≤ − h(l) βγ (t i)<br />

h ′ βγ (t i) .<br />

The initial case when i = 0 holds by construction.<br />

assume that the hypothesis holds for i. We will estimate<br />

So let us<br />

β i+1 ≤ ‖Df(X i+1 ) † Df(X i )‖‖Df(X i ) † f(X i+1 )‖ (9.4)<br />

and<br />

γ i+1 ≤ ‖Df(X i+1 ) † Df(X i )‖ ‖Df(X i) † D k f(X i+1 )‖<br />

. (9.5)<br />

k!<br />

By construction, f(X i ) + Df(X i )(X i+1 − X i ) = 0. The Taylor<br />

expansion of f at X i is therefore<br />

Df(X i ) † f(X i+1 ) = ∑ k≥2<br />

Passing to norms,<br />

while we know from (7.14) that<br />

ˆβ i+1 = − h βγ(t i+1 )<br />

h ′ βγ (t i)<br />

From Lemma 9.4,<br />

Df(X i ) † D k f(X i )(X i+1 − X i ) k<br />

k!<br />

‖Df(X i ) † f(X i+1 )‖ ≤ β2 i γ i<br />

1 − γ i<br />

= β(h βγ, t i ) 2 γ(h βγ , t i )<br />

1 − γ(h βγ , t i )<br />

‖Df(X i+1 ) † Df(X i )‖ ≤ (1 − β iγ i ) 2<br />

.<br />

ψ(β i γ i )<br />

= ˆβ 2 i ˆγ i<br />

1 − ˆγ i

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