21.06.2015 Views

Nonlinear Equations - UFRJ

Nonlinear Equations - UFRJ

Nonlinear Equations - UFRJ

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

[SEC. 1.1: BÉZOUT’S THEOREM 3<br />

tions<br />

f 1 (x) = ∑<br />

|a|≤d 1<br />

f 1a x a<br />

f n (x) = ∑<br />

.<br />

|a|≤d n<br />

f na x a<br />

has exactly B = d 1 d 2 . . . d n roots x in C n . The number of isolated<br />

roots is never more than B.<br />

This can be restated in terms of homogeneous polynomials with<br />

roots in projective space P n . We introduce a new variable x 0 (the<br />

homogenizing variable) so that all monomials in the i-th equation<br />

have the same degree. We denote by fi h the homogenization of f i ,<br />

f h i (x 0 , . . . , x n ) = x di<br />

0 f i<br />

(<br />

x1<br />

, . . . , x )<br />

n<br />

x 0 x 0<br />

Once this is done, if (x 0 , · · · , x n ) is a simultaneous root of all fi h ’s, so<br />

is (λx 0 , · · · , λx n ) for all λ ∈ C. Therefore, we count complex ‘lines’<br />

through the origin instead of points in C n+1 .<br />

The space of complex lines through the origin is known as the<br />

projective space P n . More formally, P n is the quotient of (C n+1 )≠0<br />

by the multiplicative group C × .<br />

A root (z 1 , . . . , z n ) ∈ C n of f corresponds to the line (λ, λz 1 , . . . ,<br />

λz n ), also denoted by (1 : z 1 : · · · : z n ). That line is a root of f h .<br />

Roots (z 0 : · · · : z n ) of f h are of two types: if z 0 ≠ 0, then<br />

z corresponds to the root (z 1 /z 0 , . . . , z n /z 0 ) of f, and is said to be<br />

finite. Otherwise, z is said to be at infinity.<br />

We will give below a short and sketchy proof of Bézout’s theorem.<br />

It is based on four basic facts, not all of them proved here.<br />

The first fact is that Zariski open sets are path-connected. Suppose<br />

that V is a Zariski closed set, and that y 1 ≠ y 2 are not points of<br />

V . (This already implies V ≠ C n ). We claim that there is a path

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!