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Nonlinear Equations - UFRJ

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[SEC. 6.3: GEOMETRIC CONSIDERATIONS 77<br />

Thus,<br />

ˆm ∗ η(u, v) = D 2 ( 1 log K(x, x))(re(u), im(v))<br />

2<br />

using Lemma 5.10.<br />

−D 2 ( 1 log K(x, x))(im(u), re(v))<br />

2<br />

= 2 n 〈u, Jv〉 x+<br />

√ −1y<br />

= 2 n ω x+<br />

√ −1y (u, v)<br />

As a consequence toward the proof of Kushnirenko’s theorem, we<br />

note that<br />

Proposition 6.8.<br />

E(n M (f)) = n!Vol(A)<br />

Theo-<br />

Proof. The preimage M = m −1 (A) has volume π n Vol(A).<br />

rem 5.11) implies then that expected number of roots is<br />

E(n M (f)) = 1<br />

π n ∫M<br />

n∧<br />

i=1<br />

ω = n! Vol(M) = n!Vol(A).<br />

πn 6.3 Geometric considerations<br />

To achieve the proof of the Kushnirenko theorem, we still need to<br />

prove that the number of roots is generically constant. The following<br />

step in the proof of that fact was used implicitly in other occasions:<br />

Lemma 6.9. Let M be a holomorphic manifold, and F = F 1 ×· · ·×F n<br />

be a product of fewspaces. Let V ⊂ F × M and let π 1 : V → F and<br />

π 2 : V → M be the canonical projections.<br />

Assume that (f t ) t∈[0,1] is a smooth path in F and that for all t, f t<br />

is a regular value for f t . Let v 0 ∈ π1 −1 (f 0).<br />

Then, the path f t can be lifted to a path v t with π 1 (v t ) = f t in an<br />

interval I such that either I = [0, 1] or I = [0, τ), τ < 1 and π 2 (v t )<br />

diverges for t → τ.

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