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VRIJE UNIVERSITEIT BRUSSEL Acoustics - the Dept. of ...

VRIJE UNIVERSITEIT BRUSSEL Acoustics - the Dept. of ...

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5.1. MEASURING SOUND INSULATION 83Figure 5.2: Laboratory for measuring sound insulation <strong>of</strong> a separating structure.measurements in laboratory). Because <strong>of</strong> <strong>the</strong> fact that sound transmission isa transfer <strong>of</strong> energy, we will consider <strong>the</strong> sound intensity levels :R = L I1 −L I2 = 10log I 1I 2(5.2)with I 1 <strong>the</strong> incident intensity and I 2 <strong>the</strong> transmitted intensity at <strong>the</strong> o<strong>the</strong>rside <strong>of</strong> <strong>the</strong> wall. Now, <strong>the</strong> intensity level I 2 transmitted through <strong>the</strong> wallis quite difficult to measure because also <strong>the</strong> walls will contribute to <strong>the</strong>measured sound level in <strong>the</strong> receiving room (in <strong>the</strong> normalized laboratory<strong>the</strong> hard walls create a diffuse field). For this reason we will use <strong>the</strong> meanintensity Ī2 in <strong>the</strong> receiving room and convert this to <strong>the</strong> intensity I 2 . Bothintensities are related to each o<strong>the</strong>r by :I 2 S = Ī2A (<strong>the</strong> transmitted energyis absorbed by <strong>the</strong> walls with total absorption A). This means that we canwrite <strong>the</strong> sound insulation as follows :R = 10log I 1I 2= 10log p2 1because I 1 = p2 14ρcI 2 4ρcin a diffuse field.p 2 1= 10log4ρcĪ2 A Swith SI 2 = AĪ2= 10log p2 1p 2 2 A S

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