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"Frontmatter". In: Analysis of Financial Time Series

"Frontmatter". In: Analysis of Financial Time Series

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SIMPLE ARMA MODELS 55This representation shows the dependence <strong>of</strong> the current return r t on the past returnsr t−i ,wherei > 0. The coefficients {π i } are referred to as the π-weights <strong>of</strong> an ARMAmodel. To show that the contribution <strong>of</strong> the lagged value r t−i to r t is diminishing asi increases, the π i coefficient should decay to zero as i increases. An ARMA(p, q)model that has this property is said to be invertible. For a pure AR model, θ(B) = 1so that π(B) = φ(B), which is a finite-degree polynomial. Thus, π i = 0fori >p, and the model is invertible. For other ARMA models, a sufficient condition forinvertibility is that all the zeros <strong>of</strong> the polynomial θ(B) are greater than unity inmodulus. For example, consider the MA(1) model r t = (1 − θ 1 B)a t . The zero <strong>of</strong> thefirst order polynomial 1 − θ 1 B is B = 1/θ 1 . Therefore, an MA(1) model is invertibleif | 1/θ 1 | > 1. This is equivalent to | θ 1 | < 1.From the AR representation in Eq. (2.28), an invertible ARMA(p, q) series r t is alinear combination <strong>of</strong> the current shock a t and a weighted average <strong>of</strong> the past values.The weights decay exponentially for more remote past values.MA RepresentationAgain, using the result <strong>of</strong> long division in Eq. (2.26), an ARMA(p, q) model canalso be written asr t = µ + a t + ψ 1 a t−1 + ψ 2 a t−2 +···=µ + ψ(B)a t , (2.29)where µ = E(r t ) = φ 0 /(1 − φ 1 −···−φ p ). This representation shows explicitlythe impact <strong>of</strong> the past shock a t−i (i > 0) on the current return r t . The coefficients{ψ i } are referred to as the impulse response function <strong>of</strong> the ARMA model. For aweakly stationary series, the ψ i coefficients decay exponentially as i increases. Thisis understandable as the effect <strong>of</strong> shock a t−i on the return r t should diminish overtime. Thus, for a stationary ARMA model, the shock a t−i does not have a permanentimpact on the series. If φ 0 ̸= 0, then the MA representation has a constant term,which is the mean <strong>of</strong> r t [i.e., φ 0 /(1 − φ 1 −···−φ p ].The MA representation in Eq. (2.29) is also useful in computing the variance <strong>of</strong> aforecast error. At the forecast origin h, we have the shocks a h , a h−1 ,....Therefore,the l-step ahead point forecast isand the associated forecast error isˆr h (l) = µ + ψ l a h + ψ l+1 a h−1 +···, (2.30)e h (l) = a h+l + ψ 1 a h+l−1 +···+ψ l−1 a h+1 .Consequently, the variance <strong>of</strong> l-step ahead forecast error isVar[e h (l)] =(1 + ψ 2 1 +···+ψ2 l−1 )σ 2 a , (2.31)which, as expected, is a nondecreasing function <strong>of</strong> the forecast horizon l.

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