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The Physiology of Flowering Plants - KHAM PHA MOI

The Physiology of Flowering Plants - KHAM PHA MOI

The Physiology of Flowering Plants - KHAM PHA MOI

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ANAEROBIC RESPIRATION 49Table 2.3 <strong>The</strong> balance sheet for respiratory production <strong>of</strong> molecules <strong>of</strong> ATPper 1 molecule <strong>of</strong> glucose, assuming complete coupling and complete oxidationvia glycolysis, Krebs cycle and cytochrome oxidase system.Substrate level oxidation in glycolysis 4Substrate level oxidation in Krebs cycle 2Terminal oxidation, 2 NADH from glycolysis 4Terminal oxidation, 8 NADH from Krebs cycle 24Terminal oxidation, 2 succinate 4Total produced 38Used up in glycolysis, priming reactions 2Net gain 36the Krebs cycle, with terminal oxidation through cytochrome oxidase,one can add up the ATP molecules per 1 molecule glucose(Table 2.3).<strong>The</strong> NADH from glycolysis, reacting with mitochondria from theoutside, is oxidized with the production <strong>of</strong> only 2 ATP per NADH,whilst mitochondrially produced coenzyme oxidation yields 3 ATPper 1 NADH. <strong>The</strong> free energy <strong>of</strong> complete oxidation <strong>of</strong> glucose is2880 kJ mol –1 . <strong>The</strong> free energy <strong>of</strong> hydrolysis <strong>of</strong> ATP is highly dependenton factors such as ATP concentration and pH, but under cellularconditions is at least 42 kJ mol –1 . Assuming this value, a gain <strong>of</strong>36 ATP per molecule <strong>of</strong> glucose is equivalent to an energy conservation<strong>of</strong> [36 42], 1512 kJ mol –1 , or 52% <strong>of</strong> the total available, a veryhigh degree <strong>of</strong> energy conservation. (<strong>The</strong> value would be pushedeven higher if phosphorylated sugars enter the glycolytic pathway,Section 2.8.2.)<strong>The</strong> calculation in Table 2.3 is, however, based on an assumption<strong>of</strong> complete coupling <strong>of</strong> substrate breakdown and terminal oxidation toATP synthesis. This is unlikely to be the situation in a cell, at least notin all circumstances. Any NADH which is used in reductive reactionsdoes not yield ATP, and terminal oxidation by the alternative oxidaseproduces only 1 ATP per molecule <strong>of</strong> NADH oxidized. <strong>The</strong> 12 NADPHformed per molecule <strong>of</strong> glucose in the PPP could theoretically beoxidized by the mitochondria with the production <strong>of</strong> 24 ATP, but,as stated, the PPP probably provides NADPH mainly for reductivereactions rather than for terminal oxidation. It is therefore not possibleto say exactly how much ATP is produced per glucose moleculein a particular situation.2.10 Anaerobic respiration2.10.1 Occurrence and endurance <strong>of</strong> anaerobiosis in plants<strong>Flowering</strong> plants are obligate aerobes: no flowering plant can completeits life cycle without O 2 . Most flowering plant organs, except dormant

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