chapter 1

Chapter 2: Probabilityb. P(0 def in batch | 1 def in sample) = 0.06P(1 def in batch | 1 def in sample) = = . 457.06 + .0712.0712= ..06 + .0712P(2 def in batch | 1 def in sample) = 54362. Using a tree diagram, B = basic, D = deluxe, W = warranty purchase, W’ = no warranty. 4 × .3 = .12 = P(B ∩ W ). 4×.7 = .28 = P ( B ∩W′). 6×.5 = .30 = P(D ∩W)P(B ∩W)P(W ). 6 × .5 = .30 = P ( D ∩ W ′).12.30 + .12.12.42We want P(B|W) = = = = . 285776