chapter 1

CHAPTER 10Section 10.11.a. H o will be rejected if f ≥ F .= 3. 06 (since I – 1 = 4, and I ( J – 1 ) = (5)(3) = 15 ).05,4,15MSTr=MSE2673.3The computed value of F is f = = 2. 44 . Since 2.44 is not≥ 3.061094.2, H o is not rejected. The data does not indicate a difference in the mean tensilestrengths of the different types of copper wires.b. 3. 06F and F 2. 36. 05,4,15=. 10,4,15=values, it can be said that .05 < p-value < .10., and our computed value of 2.44 is between those2.Type of Box x s1 713.00 46.552 756.93 40.343 698.07 37.204 682.02 39.87Grand mean = 712.516MSTr =4 − 1MSE =4MSTrf =MSE22[( 713.00 − 712.51) + ( 756.93 − 712.51) 2+ ( 698.07 − 712.51)2+ ( 682.02 − 712.51) ] = 6,223. 0604222[( 46.55) + ( 40.34) + ( 37.20)+ ( 39.87) ] = 1,691. 91881 2F6,223.0604==1,691.91883.10. 05,3,20=3.6783.678 > 3.10, so reject H o . There is a difference in compression strengths among the four boxtypes.295