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Chapter 12: Simple Linear Regression and Correlation36.a. A scatter plot, generated by Minitab, supports the decision to use linear regressionanalysis.1.00.9mist droplets0.80.70.60.50.40100200300400500600700800900 1000fluid flow velocityb. We are asked for the coefficient of determination, r 2 . From the Minitab output, r 2 = .931( which is close to the hand calculated value, the difference being accounted for byround-off error.)c. Increasing x from 100 to 1000 means an increase of 900. If, as a result, the average ywere to increase by .6, the slope would be = . 0006667 . We should test the900H : = . 1vs. H : < . 10006667hypotheses 0006667o.00062108 − .0006667t == −.601.00007579a.6. The test statistic is, which is not significant. There is notsufficient evidence that with an increase from 100 to 1000, the true average increase in yis less than .6.d. We are asked for a confidence interval for β1. Using the values from the Minitaboutput, we have . 00062108 ± 2.776 (.00007579) = (.00041069,.00083147)369

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