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CHAPTER 6Section 6.11.a. We use the sample mean, x to estimate the population mean µ .Σxi219.80µ ˆ = x = = = 8.1407n 27~ = 7.b. We use the sample median, x 7 (the middle observation when arranged inascending order).c. We use the sample standard deviation,s = s2=( 219.8)1860.94−27262= 1.660d. With “success” = observation greater than 10, x = # of successes = 4, andxp ˆ = = 4n=27.14811.660e. We use the sample (std dev)/(mean), or = = . 2039sx8.14072.ˆ =a. With X = # of T’s in the sample, the estimator is p = X ; x 10,so p = , . 50 .n10ˆ =2016ˆ =20b. Here, X = # in sample without TI graphing calculator, and x = 16, so p = . 80205

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