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SPA 3e_ Teachers Edition _ Ch 6

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416<br />

C H A P T E R 6 • Sampling Distributions<br />

15. (a) Statistics (ii) and (iii) both appear<br />

to be unbiased because the mean of each<br />

sampling distribution is very close to the<br />

value of the population parameter.<br />

(b) Statistic (ii); while both statistics<br />

(ii) and (iii) are unbiased, statistic (ii) has<br />

lower variability.<br />

16. (a)<br />

10 + 5 + 10 + 7 + 9 41<br />

m =<br />

=<br />

5<br />

5 = 8.2<br />

(b)<br />

Sample #1: Abigail (10), x 5 7.5<br />

Bobby (5)<br />

Sample #2: Abigail (10), x 5 10<br />

Carlos (10)<br />

Sample #3: Abigail (10), x 5 8.5<br />

DeAnna (7)<br />

Sample #4: Abigail (10), x 5 9.5<br />

Emily (9)<br />

Sample #5: Bobby (5), x 5 7.5<br />

Carlos (10)<br />

Sample #6: Bobby (5), x 5 6<br />

DeAnna (7)<br />

Sample #7: Bobby (5), x 5 7<br />

Emily (9)<br />

Sample #8: Carlos (10), x 5 8.5<br />

DeAnna (7)<br />

Sample #9: Carlos (10), x 5 9.5<br />

Emily (9)<br />

Sample #10: DeAnna (7), x 5 8<br />

Emily (9)<br />

(c)<br />

d d d<br />

d<br />

d d d d d<br />

6 6.5 7 7.5 8 8.5 9 9.5 10<br />

Sample mean quiz score<br />

m x =<br />

7.5 + 10 + 8.5 + 9.5 + 7.5 +<br />

6 + 7 + 8.5 + 9.5 + 8<br />

10<br />

= 82<br />

10 = 8.2.<br />

Yes, the sample mean is an unbiased<br />

estimator of the population mean. The<br />

mean of the sampling distribution is equal<br />

to 8.2, which is the value of the population<br />

mean.<br />

(a) Which statistics are unbiased estimators? Justify<br />

your answer.<br />

(b) Which statistic does the best job of estimating the<br />

parameter? Explain.<br />

Extending the Concepts<br />

16. More about means In the Exercises for Lesson 6.1,<br />

you were introduced to the following population of<br />

2 male students and 3 female students, along with<br />

their quiz scores:<br />

Abigail 10 Bobby 5 Carlos 10 DeAnna 7 Emily 9<br />

(a) Calculate the mean quiz score for the entire population.<br />

(b) List all 10 possible SRSs of size n 5 2, calculate<br />

the mean quiz score for each sample, and display<br />

the sampling distribution of the sample mean in a<br />

dotplot.<br />

(c) Calculate the mean of the sampling distribution<br />

from part (b). Is the sample mean an unbiased estimator<br />

of the population mean? Explain.<br />

17. More about proportions In the Exercises for<br />

Lesson 6.1, you were introduced to the following<br />

population of 2 male students and 3 female<br />

students, along with their quiz scores:<br />

Abigail 10 Bobby 5 Carlos 10 DeAnna 7 Emily 9<br />

(a) Calculate the proportion of females in the entire<br />

population.<br />

(b) List all 10 possible SRSs of size n 5 2, calculate the<br />

proportion of females for each sample, and display<br />

the sampling distribution of the sample proportion<br />

in a dotplot.<br />

(c) Calculate the mean of the sampling distribution<br />

from part (b). Is the sample proportion an unbiased<br />

estimator of the population proportion? Explain.<br />

Recycle and Review<br />

18. Students and housing (4.3, 4.4) There are 104<br />

students in Professor Negroponte’s statistics class,<br />

49 males and 55 females. Sixty of the students live in<br />

the dorms and the rest live off campus. Twenty of the<br />

males live off-campus. <strong>Ch</strong>oose a student at random<br />

from this class. Let Event M 5 the student is male and<br />

Event D 5 the student lives in the dorms.<br />

(a) Construct a Venn diagram to represent the outcomes<br />

of this chance process using the events M<br />

and D.<br />

(b) Find each of the following probabilities and interpret<br />

them in context.<br />

(i) P(M c D) (ii) P(M C d D) (iii) P(D k M)<br />

19. Students and homework (5.3, 5.4) Refer to Exercise<br />

18. At the beginning of each day that Professor<br />

Negroponte’s class meets, he randomly selects a<br />

member of the class to present the solution to a homework<br />

problem. Suppose the class meets 40 times during<br />

the semester and the selections are made with<br />

replacement. Let X 5 the number of times a female<br />

student is selected to present a solution.<br />

(a) Is X a binomial random variable? Justify your<br />

answer.<br />

(b) Calculate the mean and standard deviation of X.<br />

(c) For the first 10 meetings of the class, Professor Negroponte<br />

selects only 1 female student to solve a problem.<br />

Is there convincing evidence that his selection<br />

process is not really random? Support your answer<br />

with an appropriate probability calculation.<br />

17. (a) p = 3 5 = 0.6<br />

(b)<br />

Sample #1: Abigail, Bobby p^ 5 0.5<br />

Sample #2: Abigail, Carlos p^ 5 0.5<br />

Sample #3: Abigail, DeAnna p^ 5 1<br />

Sample #4: Abigail, Emily p^ 5 1<br />

Sample #5: Bobby, Carlos p^ 5 0<br />

Sample #6: Bobby, DeAnna p^ 5 0.5<br />

Sample #7: Bobby, Emily p^ 5 0.5<br />

Sample #8: Carlos, DeAnna p^ 5 0.5<br />

Sample #9: Carlos, Emily p^ 5 0.5<br />

Sample #10: DeAnna, Emily p^ 5 1<br />

d<br />

d<br />

d d dd d d<br />

0 0.5 1<br />

Sample proportion of female<br />

Starnes_<strong>3e</strong>_CH06_398-449_Final.indd 416<br />

(c)<br />

0.5 + 0.5 + 1 + 1 + 0 +<br />

0.5 + 0.5 + 0.5 + 0.5 + 1<br />

m p^ =<br />

= 6<br />

10<br />

10 = 0.6.<br />

Yes, the sample proportion is an unbiased<br />

estimator of the population proportion. The<br />

mean of the sampling distribution is equal<br />

to 0.6, which is the value of the population<br />

proportion.<br />

18. (a)<br />

Male 20 29 Dorms 31<br />

24<br />

20 + 29 + 31<br />

(b) (i) P(M c D) = P(M or D) =<br />

104<br />

= 80 = 0.769. There is about a 77% chance<br />

104<br />

that a randomly selected student is a male or<br />

lives in the dorm.<br />

(ii) P(M C d D) = P(M C 31<br />

and D)=<br />

104 = 0.298.<br />

There is about a 30% chance that a randomly<br />

selected student is not a male and lives in the<br />

dorm.<br />

P(D and M)<br />

(iii) P(D 0 M) = = 29∙104<br />

P(M) 49∙104 = 29<br />

49<br />

= 0.592. There is about a 59% chance that a<br />

randomly selected student lives in the dorm,<br />

given that the student is a male.<br />

Answer 19 is on page 417<br />

18/08/16 5:00 PMStarnes_<strong>3e</strong>_CH0<br />

416<br />

C H A P T E R 6 • Sampling Distributions<br />

Starnes_<strong>3e</strong>_ATE_CH06_398-449_v3.indd 416<br />

11/01/17 3:54 PM

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