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SPA 3e_ Teachers Edition _ Ch 6

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446<br />

C H A P T E R 6 • Sampling Distributions<br />

Answers to <strong>Ch</strong>apter 6 Review<br />

Exercises<br />

1. Population: All eggs shipped in one<br />

day. Sample: The 200 eggs examined.<br />

Parameter: The proportion p of eggs<br />

shipped that day that had salmonella.<br />

Statistic: The proportion of eggs in<br />

the sample that had salmonella,<br />

p^ = 9<br />

200 = 0.045.<br />

2. (a)<br />

Sample #1: 64, 66, 71 Median 5 66<br />

Sample #2: 64, 66, 73 Median 5 66<br />

Sample #3: 64, 66, 76 Median 5 66<br />

Sample #4: 64, 71, 73 Median 5 71<br />

Sample #5: 64, 71, 76 Median 5 71<br />

Sample #6: 64, 73, 76 Median 5 73<br />

Sample #7: 66, 71, 73 Median 5 71<br />

Sample #8: 66, 71, 76 Median 5 71<br />

Sample #9: 66, 73, 76 Median 5 73<br />

Sample #10: 71, 73, 76 Median 5 73<br />

d<br />

d<br />

d<br />

d<br />

d<br />

d<br />

66 67 68 69 70 71 72 73<br />

Sample median book length<br />

66 + 66 + 66 + 71 + 71 +<br />

71 + 71 + 73 + 73 + 73<br />

(b) m median =<br />

10<br />

= 701<br />

10 = 70.1<br />

The sample median is a biased estimator<br />

of the population median. The mean<br />

of the sampling distribution is equal to<br />

70.1, which is less than the value of the<br />

population median of 71.<br />

(c) The sampling distribution of the<br />

sample median will be less variable<br />

because the sample size is larger. The<br />

estimated median book length will<br />

typically be closer to the true median<br />

book length. In other words, the estimate<br />

will be more precise.<br />

3. (a) m X = np = 500(0.24) = 120<br />

people; s X = "np(1 − p)<br />

= "500(0.24)(1 − 0.24) = 9.55 people<br />

(b) If many samples of size 500 were<br />

taken, the number of people who are<br />

under 18 years old would typically vary<br />

by about 9.55 from the mean of 120.<br />

(c) The sampling distribution of X<br />

is approximately normal because<br />

np = 500(0.24) = 120 ≥ 10 and<br />

n(1 − p) = 500(1 − 0.24) = 380 ≥ 10<br />

j<br />

j<br />

j<br />

We can use sampling distributions to determine<br />

what values of a statistic are likely to happen by<br />

chance alone and how much a statistic typically<br />

varies from the parameter it is trying to estimate.<br />

A statistic used to estimate a parameter is an<br />

unbiased estimator if the mean of its sampling<br />

distribution is equal to the value of the parameter<br />

being estimated. That is, the statistic doesn’t<br />

consistently overestimate or consistently underestimate<br />

the value of the parameter when many<br />

random samples are selected.<br />

The sampling distribution of any statistic will<br />

have less variability when the sample size is larger.<br />

That is, the statistic will be a more precise estimator<br />

of the parameter with larger sample sizes.<br />

Sample Counts and Sample Proportions<br />

j<br />

j<br />

Let X 5 the number of successes in a random sample<br />

of size n from a large population with proportion<br />

of successes p. The sampling distribution of a<br />

sample count X describes the distribution of values<br />

taken by the sample count X in all possible samples<br />

of the same size from the same population.<br />

j The mean of the sampling distribution of X<br />

is m X = np. The mean describes the average<br />

value of X in repeated random samples.<br />

j The standard deviation of the sampling distribution<br />

of X is s X = !np(1 − p). The standard<br />

deviation describes how far the values of X typically<br />

vary from m X in repeated random samples.<br />

j The shape of the sampling distribution of X<br />

will be approximately normal when the Large<br />

Counts condition is met: np ≥ 10 and n(1 2 p)<br />

≥10.<br />

Let p^ 5 the proportion of successes in a random<br />

sample of size n from a large population with proportion<br />

of successes p. The sampling distribution of a<br />

sample proportion p^ describes the distribution of values<br />

taken by the sample proportion p^ in all possible<br />

samples of the same size from the same population.<br />

j The mean of the sampling distribution of p^ is<br />

m p^ = p. The mean describes the average value<br />

of p^ in repeated random samples.<br />

j The standard deviation of the sampling<br />

p(1 − p)<br />

distribution of p^ is s p^ 5 . The<br />

Å n<br />

Starnes_<strong>3e</strong>_CH06_398-449_Final.indd 446<br />

100 − 120<br />

(d) z = = −2.09;<br />

9.55<br />

110 − 120<br />

z = = −1.05<br />

9.55<br />

P(100 ≤ X ≤ 110) ≈ P(−2.09 ≤<br />

Z ≤ − 1.05) = 0.1469 − 0.0183 = 0.1286<br />

Using technology: Applet/normalcdf<br />

(lower:100, upper:110, mean:120, SD:9.55)<br />

5 0.1294<br />

j<br />

standard deviation describes how far the values<br />

of p^ typically vary from p in repeated random<br />

samples.<br />

The shape of the sampling distribution of<br />

p^ will be approximately normal when the<br />

Large Counts condition is met: np ≥ 10 and<br />

n(1 2 p) ≥ 10.<br />

Sample Means<br />

j<br />

j<br />

Let x 5 the mean of a random sample of size n<br />

from a large population with mean m and standard<br />

deviation s. The sampling distribution of<br />

a sample mean x describes the distribution of<br />

values taken by the sample mean x in all possible<br />

samples of the same size from the same<br />

population.<br />

j The mean of the sampling distribution of x is<br />

m x = m. The mean describes the average value<br />

of x in repeated random samples.<br />

j The standard deviation of the sampling distribution<br />

of x is s− x = s . The standard deviation<br />

describes how far the values of x typically<br />

"n<br />

vary from m in repeated random samples.<br />

The shape of the sampling distribution of<br />

x will be approximately normal when the<br />

Normal/Large Sample condition is met: The<br />

population is normal or the sample size is large<br />

(n ≥ 30). The fact that the sampling distribution<br />

of x becomes approximately normal—<br />

even when the population is non-normal—as<br />

the sample size increases is called the central<br />

limit theorem.<br />

Probability Calculations<br />

j<br />

j<br />

When the sampling distribution of a statistic is<br />

approximately normal, you can use z-scores and<br />

Table A or technology to do probability calculations<br />

involving the statistic.<br />

To determine which sampling distribution to use,<br />

consider whether the variable of interest is categorical<br />

or quantitative. If it is categorical, use the<br />

sampling distribution of a sample count X or the<br />

sampling distribution of a sample proportion p^ . If<br />

it is quantitative, use the sampling distribution of<br />

a sample mean x.<br />

TRM chapter 6 Review Exercise Videos<br />

Video solutions to the <strong>Ch</strong>apter 6 Review<br />

Exercises are available to teachers and<br />

students. Access them by clicking on the link<br />

in the TE-book, logging into the Teacher’s<br />

Resource site, or accessing this resource<br />

on the TRFD.<br />

18/08/16 5:04 PMStarnes_<strong>3e</strong>_CH0<br />

446<br />

C H A P T E R 6 • Sampling Distributions<br />

Starnes_<strong>3e</strong>_ATE_CH06_398-449_v3.indd 446<br />

11/01/17 3:58 PM

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