14.04.2018 Views

ch01-03 stress & strain & properties

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

<strong>03</strong> Solutions 46060 5/7/10 8:45 AM Page 14<br />

© 2010 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as they currently<br />

exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher.<br />

3–17. A tension test was performed on an aluminum<br />

2014-T6 alloy specimen. The resulting <strong>stress</strong>–<strong>strain</strong> diagram<br />

is shown in the figure. Estimate (a) the proportional limit,<br />

(b) the modulus of elasticity, and (c) the yield strength<br />

based on a 0.2% <strong>strain</strong> offset method.<br />

s (ksi)<br />

70<br />

60<br />

50<br />

40<br />

30<br />

20<br />

10<br />

0<br />

0.02 0.04 0.06 0.08 0.10<br />

0.002 0.004 0.006 0.008 0.010<br />

P (in./in.)<br />

Proportional Limit and Yield Strength: From the <strong>stress</strong>–<strong>strain</strong> diagram, Fig. a,<br />

s pl = 44 ksi<br />

s Y = 60 ksi<br />

Ans.<br />

Ans.<br />

Modulus of Elasticity: From the <strong>stress</strong>–<strong>strain</strong> diagram, the corresponding <strong>strain</strong> for<br />

s PL = 44 ksi is e pl = 0.004 in.>in. Thus,<br />

E = 44 - 0<br />

0.004 - 0 = 11.0(1<strong>03</strong> ) ksi<br />

Ans.<br />

Modulus of Resilience: The modulus of resilience is equal to the area under the<br />

14

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!