ch01-03 stress & strain & properties
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01 Solutions 46060 5/6/10 2:43 PM Page 67<br />
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*1–100. The hanger is supported using the rectangular<br />
pin. Determine the required thickness t of the hanger, and<br />
dimensions a and b if the suspended load is P = 60 kN.<br />
The allowable tensile <strong>stress</strong> is (s t ) allow = 150 MPa, the<br />
allowable bearing <strong>stress</strong> is (s b ) allow = 290 MPa, and the<br />
allowable shear <strong>stress</strong> is t allow = 125 MPa.<br />
75 mm<br />
a<br />
a<br />
20 mm<br />
b<br />
10 mm<br />
t<br />
P<br />
37.5 mm<br />
37.5 mm<br />
Allowable Normal Stress: For the hanger<br />
(s t ) allow = P A ; 150A106 B = 60(1<strong>03</strong> )<br />
(0.075)t<br />
t = 0.005333 m = 5.33 mm<br />
Ans.<br />
Allowable Shear Stress: For the pin<br />
t allow = V A ; 125A106 B = 30(1<strong>03</strong> )<br />
(0.01)b<br />
b = 0.0240 m = 24.0 mm<br />
Ans.<br />
Allowable Bearing Stress: For the bearing area<br />
(s b ) allow = P A ; 290A106 B = 30(1<strong>03</strong> )<br />
(0.0240) a<br />
a = 0.00431 m = 4.31 mm<br />
Ans.<br />
67
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