ch01-03 stress & strain & properties

01 Solutions 46060 5/6/10 2:43 PM Page 45
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*1–64. The triangular blocks are glued along each side of
the joint. A C-clamp placed between two of the blocks is
used to draw the joint tight. If the glue can withstand a
maximum average shear stress of 800 kPa, determine the
maximum allowable clamping force F.
50 mm
45
F
25 mm
glue
Internal Loadings: The shear force developed on the glued shear plane can be
obtained by writing the force equation of equilibrium along the x axis with
reference to the free-body diagram of the triangular block, Fig. a.
F
: + ©F x = 0; F cos 45° - V = 0 V = 2 2
2 F
Average Normal and Shear Stress: The area of the glued shear plane is
A = 0.05(0.025) = 1.25(10 - 3 )m 2 . We obtain
t avg = V A ; 800(103 ) =
2 2
2 F
1.25(10 - 3 )
F = 1414 N = 1.41 kN
Ans.
•1–65. The triangular blocks are glued along each side of
the joint. A C-clamp placed between two of the blocks is
used to draw the joint tight. If the clamping force is
F = 900 N, determine the average shear stress developed
in the glued shear plane.
Internal Loadings: The shear force developed on the glued shear plane can be
obtained by writing the force equation of equilibrium along the x axis with
reference to the free-body diagram of the triangular block, Fig. a.
50 mm
45
F
25 mm
glue
F
: + ©F x = 0; 900 cos 45° - V = 0 V = 636.40 N
Average Normal and Shear Stress: The area of the glued shear plane is
A = 0.05(0.025) = 1.25(10 - 3 )m 2 . We obtain
t avg = V A = 636.40
1.25(10 - 3 = 509 kPa
)
Ans.
45