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ch01-03 stress & strain & properties

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01 Solutions 46060 5/6/10 2:43 PM Page 33<br />

© 2010 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as they currently<br />

exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher.<br />

•1–49. The beam is supported by a pin at A and a short<br />

link BC. Determine the maximum magnitude P of the loads<br />

the beam will support if the average shear <strong>stress</strong> in each pin<br />

is not to exceed 80 MPa. All pins are in double shear as<br />

shown, and each has a diameter of 18 mm.<br />

C<br />

30<br />

P 4P 4P 2P<br />

0.5m<br />

0.5 m<br />

1 m 1.5 m 1.5 m<br />

B<br />

A<br />

a +©M A = 0; 2P(0.5) + 4P(2) + 4P(3.5) + P(4.5) - (T CB sin 30°)(5) = 0<br />

T CB = 11P<br />

: + ©F x = 0; A x - 11P cos 30° = 0<br />

A x = 9.5263P<br />

+ c ©F y = 0; A y - 11P + 11P sin 30° = 0<br />

A y = 5.5P<br />

F A = 2 (9.5263P) 2 + (5.5P) 2 = 11P<br />

Require;<br />

t = V A ; 80(106 ) = 11P>2<br />

p<br />

4 (0.018)2<br />

P = 3.70 kN<br />

Ans.<br />

33

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