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Fundamentals of Mathematics, 2008a

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307<br />

5.4.1.1 Sample Set A<br />

Find the following sums and dierences.<br />

Example 5.14<br />

8 3 5 + 5 1 4<br />

. Convert each mixed number to an improper fraction.<br />

8 3 5 = 5·8+3<br />

5<br />

= 40+3<br />

5<br />

= 43 5<br />

5 1 4 = 4·5+1<br />

4<br />

= 20+1<br />

4<br />

= 21 4 Now add the improper fractions 43 5 and 21 4 .<br />

43<br />

5 + 21<br />

4<br />

The LCD = 20.<br />

43<br />

5 + 21 4<br />

= 43·4<br />

20 + 21·5<br />

20<br />

= 172<br />

20 + 105<br />

20<br />

172+105<br />

=<br />

20<br />

277<br />

=<br />

20<br />

Convert this improper fraction to a mixed number.<br />

= 13 17<br />

20<br />

Thus, 8 3 5 + 5 1 17<br />

4<br />

= 13<br />

20 .<br />

Example 5.15<br />

3 1 8 − 5 6<br />

. Convert the mixed number to an improper fraction.<br />

3 1 8 = 3·8+1<br />

8<br />

= 24+1<br />

8<br />

= 25 8<br />

25<br />

8 − 5 6<br />

The LCD = 24.<br />

25<br />

8 − 5 6<br />

= 25·3<br />

24 − 5·4<br />

24<br />

75<br />

=<br />

24 − 20<br />

24<br />

75−20<br />

=<br />

24<br />

55<br />

=<br />

24<br />

Convert his improper fraction to a mixed number.<br />

= 2 7 24<br />

Thus, 3 1 8 − 5 6 = 2 7<br />

24 .<br />

5.4.1.2 Practice Set A<br />

Find the following sums and dierences.<br />

Exercise 5.4.1 (Solution on p. 331.)<br />

1 5 9 + 3 2 9<br />

Exercise 5.4.2 (Solution on p. 331.)<br />

10 3 4 − 2 1 2<br />

Exercise 5.4.3 (Solution on p. 331.)<br />

2 7 8 + 5 1 4<br />

Exercise 5.4.4 (Solution on p. 331.)<br />

8 3 5 − 3<br />

10<br />

Exercise 5.4.5 (Solution on p. 331.)<br />

16 + 2 9<br />

16<br />

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