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Fundamentals of Mathematics, 2008a

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486 CHAPTER 8. TECHNIQUES OF ESTIMATION<br />

321 and 293 cluster near 300. Their sum is about 2 · 300 = 600.<br />

Thus, 706 + 321 + 293 + 684 is about<br />

(2 · 700) + (2 · 300) = 1, 400 + 600<br />

= 2, 000<br />

In fact, 706 + 321 + 293 + 684 = 2,004.<br />

8.3.1.2 Practice Set A<br />

Use the clustering method to estimate each sum.<br />

Exercise 8.3.1 (Solution on p. 506.)<br />

28 + 51 + 31 + 47<br />

Exercise 8.3.2 (Solution on p. 506.)<br />

42 + 39 + 68 + 41<br />

Exercise 8.3.3 (Solution on p. 506.)<br />

37 + 39 + 83 + 42 + 79<br />

Exercise 8.3.4 (Solution on p. 506.)<br />

612 + 585 + 830 + 794<br />

8.3.2 Exercises<br />

Use the clustering method to estimate each sum. Results may vary.<br />

Exercise 8.3.5 (Solution on p. 506.)<br />

28 + 51 + 31 + 47<br />

Exercise 8.3.6<br />

42 + 19 + 39 + 23<br />

Exercise 8.3.7 (Solution on p. 506.)<br />

88 + 62 + 59 + 90<br />

Exercise 8.3.8<br />

76 + 29 + 33 + 82<br />

Exercise 8.3.9 (Solution on p. 506.)<br />

19 + 23 + 87 + 21<br />

Exercise 8.3.10<br />

41 + 28 + 42 + 37<br />

Exercise 8.3.11 (Solution on p. 506.)<br />

89 + 32 + 89 + 93<br />

Exercise 8.3.12<br />

73 + 72 + 27 + 71<br />

Exercise 8.3.13 (Solution on p. 506.)<br />

43 + 62 + 61 + 55<br />

Exercise 8.3.14<br />

31 + 77 + 31 + 27<br />

Exercise 8.3.15 (Solution on p. 507.)<br />

57 + 34 + 28 + 61 + 62<br />

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