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Q About that latency analysis method: Do the analyzers need to have synchronized clocks?<br />

A No, that’s the cool thing about this method. You’re taking the total trip time differences on both ends.<br />

Because the difference between the differences has to be the total amount of time the packet spends in<br />

the switch or router going both ways, you divide that number by 2 to get the latency for a one-way trip.<br />

Quiz<br />

1. You install a new virus protection application on one of your servers. Instantly, you’re<br />

bombarded with complaints that the network in your building has slowed to a crawl. What should<br />

you do next?<br />

A. Run a network analyzer on your segment<br />

B. Deny everything<br />

C. Uninstall the new application<br />

D. Power down the server<br />

2. Application throughput can be found by dividing the ___________ by the ____________.<br />

A. number of workstations, number of routers<br />

B. total bytes transmitted, time elapsed<br />

C. total bytes transmitted, workstations involved<br />

D. number of workstations, time elapsed<br />

3. 10Mbps Ethernet is about ________ times faster than a T1 leased line.<br />

A. 5<br />

B. 2<br />

C. 1<br />

D. 100<br />

4. Major slowdowns can occur when _________ or __________ is not used by a network<br />

application.<br />

A. packet burst, sliding windows<br />

B. packet windows, sliding burst<br />

C. windows defenestration, burst appendix<br />

D. windows burst, sliding packets<br />

5. What’s the slowest kind of memory on any server?<br />

A. Amnesiac memory<br />

B. Cache memory<br />

C. Dynamic memory<br />

D. Virtual memory<br />

6. What constitutes a “disk-bound” application?<br />

A. When the limiting factor is how fast the disk can go<br />

B. When the application is strapped to the hard drive<br />

C. When the disk is going as fast as it can<br />

D. None of the above<br />

7. When does “oversubscription” occur?<br />

A. When a provider has more bandwidth coming in than going out

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