14.01.2013 Views

The Arithmetic of Quaternion Algebra

The Arithmetic of Quaternion Algebra

The Arithmetic of Quaternion Algebra

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

8 CHAPTER 1. QUATERNION ALGEBRA OVER A FIELD<br />

b)Every element τ in the group Gal(Ks/K) <strong>of</strong> the K-automorphism <strong>of</strong><br />

Ks induces a permutation r <strong>of</strong> 1, ..., n:<br />

τ.σi = σ r(i),<br />

it is a K-isomorphism <strong>of</strong> Hi on H r(i) , by the restriction <strong>of</strong> the mapping :<br />

τ(h ⊗ k) = h ⊗ τ(k), h ∈ H, k ∈ Ks,<br />

and a K-isomorphism <strong>of</strong> D.<br />

c) <strong>The</strong> elements <strong>of</strong> D being invariant by Gal(Ks/K) constitute a central<br />

simple algebra <strong>of</strong> dimension 4 n over K. <strong>The</strong> construction below proceeds<br />

naturally when H is a central simple L-algebra. <strong>The</strong> algebra constructed<br />

over K is denoted by Cor L/K(H). It corresponds to the co-restriction<br />

mapping under the cohomology interpretation <strong>of</strong> the Brauer groups.<br />

2. Let L/K be a separable extension <strong>of</strong> K <strong>of</strong> degree 2, and m → m be the<br />

nontrivial K-automorphism � � <strong>of</strong> L. Prove<br />

m n<br />

a) <strong>The</strong> set {g = } forms a K-algebra which is isomorphic to<br />

n m<br />

M(2, K).<br />

b) If g is invertible, prove that g−1 � �<br />

is conjugate to g by an element <strong>of</strong> the<br />

r 0<br />

form with r ∈ L<br />

0 r<br />

⋆ .<br />

1.3 Geometry<br />

In this section we assume the characteristic <strong>of</strong> the field is different from 2. For<br />

every quaternion algebra H/K we use H0 to denote the set <strong>of</strong> the quaternions<br />

with zero reduced trace. <strong>The</strong> reduced norm provides the K-vector space V, V0,<br />

the subjacent spaces <strong>of</strong> H, H0 respectively, a non-degenerate quadratic form.<br />

We denote the associated bilinear form by < h, k > for h, k ∈ V or v0. It is<br />

defined by < h, k >= t(hk, from it we deduce < h, h >= 2n(h). If the elements<br />

h, k belong to V0 we have a simple formula < h, k >= −(hk + kh). We see<br />

also that the product <strong>of</strong> two elements <strong>of</strong> H0 is an element <strong>of</strong> H0 if and only if<br />

these elements anti-commute (hk = −kh), It is also equivalent to that, these<br />

two elements are orthogonal in H0. We now study the quaternion algebra with<br />

the point <strong>of</strong> view <strong>of</strong> their quadratic spaces.<br />

Lemma 1.3.1. Let H, H ′ be two quaternion algebras over K, and V, V0, V ′ V ′<br />

0<br />

be the correspondent quadratic spaces respectively. <strong>The</strong> following properties are<br />

equivalent:<br />

(1) H and H ′ are isomorphic,<br />

(2) V and V ′ are isomorphic.<br />

(3) V0 and V ′<br />

0 are isomorphism.<br />

Pro<strong>of</strong>. (1) implies (2), because an automorphism preserving the norm induces<br />

an isomorphism. (2) implies (3) by the theorem <strong>of</strong> Witt, and the the orthogonal<br />

decomposition V = K + V0, which is deduced from (3) in §1. (3) implies (1),<br />

because an isometry preserves the orthogonality, hence if i, j ∈ H satisfy (3) in<br />

§3, then f(i) and f(j) satisfy the same relations and H = H ′ .

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!