The Arithmetic of Quaternion Algebra
The Arithmetic of Quaternion Algebra
The Arithmetic of Quaternion Algebra
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4.2. RIEMANN SURFACES 87<br />
Corollary 4.2.2. Let N be a positive real number. For every point z 0 ∈ H <strong>of</strong><br />
its real part zero, we have<br />
log N = d(z0, Nz0) = inf d(z, Nz).<br />
z∈H<br />
Pro<strong>of</strong>. d(z, Nz) = arccosh(1 + (N−1)2 x2<br />
2N (1 + y2 )) is minimal for x = 0 and equal<br />
to log N.<br />
Proposition 4.2.3. <strong>The</strong> area <strong>of</strong> a triangle whose vertices are at the infinity is<br />
equal to π.<br />
Pro<strong>of</strong>. (A picture here!!!)<br />
� �<br />
y −2 dxdy =<br />
� π<br />
0<br />
� ∞<br />
− sin θdθ y<br />
sin θ<br />
−2 dy = π.<br />
<strong>The</strong> common area <strong>of</strong> these triangles can be taken as the definition <strong>of</strong> the value<br />
π.<br />
Proposition 4.2.4. <strong>The</strong> area <strong>of</strong> a hyperbolic triangle <strong>of</strong> the angles at the vertices<br />
being θ1, θ2, θ3 is equal to π − θ1 − θ2 − θ3,<br />
Pro<strong>of</strong>. <strong>The</strong> formula is true if every vertex is at infinity. We use the Green formula<br />
if no any vertex is at the infinity: if Ci, i = 1, 2, 3 are the edges <strong>of</strong> the<br />
triangle , then � � y−2dxdy = � �<br />
i Ci dx/y<br />
Here are two pictures!!!<br />
�<br />
C dx/y = � θ 2<br />
r sin u/(−r sin u)du = α.<br />
θ1<br />
<strong>The</strong> area is thus I = α1 + α2 + α3. <strong>The</strong> total rotation <strong>of</strong> the turning normal<br />
along is the triangle 2π, and that around a vertex <strong>of</strong> angle θ is π − θ. It follows<br />
2π = �<br />
i (π − θi) + �<br />
i αi, from this we have I = π − θ1 − θ2 − θ3. It turns back<br />
to one <strong>of</strong> these two cases when one <strong>of</strong> the angles is zero (its vertex corresponds<br />
to the infinity). By the triangulation we can compute the area <strong>of</strong> a polygon.<br />
Corollary 4.2.5. <strong>The</strong> area <strong>of</strong> a hyperbolic polygon with the angles at vertices<br />
θ1, ..., θn equals (n − 2)π − (θ1 + ... + θ2).<br />
EXAMPLE. A fundamental domain <strong>of</strong> P Sl(2, Z). <strong>The</strong> group P SL(2, Z) is<br />
generated by the homographies t = z + 1 and t = −1/z. We show that the<br />
hatching domain in the picture is a fundamental set<br />
F = {z ∈ C|Imz > o, |z| ≥ 1, −1/2 ≤ Rez ≤ 1/2}.<br />
It ia a triangle with one <strong>of</strong> its vertices being at the infinity. Its area is π−2π/3 =<br />
π/3. It equals the area <strong>of</strong> the triangle without hatching, which is also a fundamental<br />
set <strong>of</strong> SL(2, Z) in H.<br />
Here is a picture!!!