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The Arithmetic of Quaternion Algebra

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42 CHAPTER 2. QUATERNION ALGEBRA OVER A LOCAL FIELD<br />

vol(Γ(p m ) = D −3/2<br />

K<br />

Np−3m .<br />

where Np is the number <strong>of</strong> elements <strong>of</strong> residue field k <strong>of</strong> K. If O = O0 is<br />

a maximal order <strong>of</strong> a quaternion algebra H/K, we have<br />

vol(O 1 0) = D −3/2<br />

K (1 − Np=2 �<br />

(Np − 1)<br />

) ·<br />

−1 , if H is a field<br />

1, if H = M(2, K) .<br />

4. (Pitzer [3]).Let {Lnr, p} be the quaternion field over K, uniquely up to<br />

isomorphism. It has the following representation<br />

� �<br />

a b<br />

H = {Lnr, p} = { |a, b ∈ Lnr}<br />

pb a<br />

where 4p is a uniform parameter <strong>of</strong> K and Lnr/K is a ramified quadratic<br />

extension. We denote simply the above matrix by [a, b]. <strong>The</strong> order<br />

O2r+1 = {[a, prb]|a, b ∈ RL} is called the canonical order <strong>of</strong> level Rp2r+1 ,<br />

where RL is the integer ring <strong>of</strong> Lnr. Verify O2r+1 is actually an order,<br />

and either directly or on the discriminant that O1 is the maximal order.<br />

Verify that an order O is isomorphic to O2r+1 for a r ≥ 0 if and only if it<br />

contains a sub-ring being isomorphic to RL. Prove, if [a, b] ∈ O × 1<br />

, it can<br />

be written as [a, b] = [a ′ , p r b ′ ][1, c], where c = b/amod(p r ) and a ′ , b ′ ∈ RL.<br />

Deduce [O × 1 : O× 2r+1 ] = Np2r .<br />

Deduce the volume <strong>of</strong> O 1 m for the Tamagawa measure is equal to<br />

vol(O 1 m) = D −3/2<br />

K (1 − Np−2 )(Np − 1) −1 Np 1−m , m ≥ 1.<br />

<strong>The</strong> formula is a natural generation <strong>of</strong> that in the above formulae.<br />

5. Maximal compact subgroup. Let K be a non-archimedean local field, and<br />

H/K be a quaternion algebra. Set X = H or K. Prove the maximal<br />

compact subgroups <strong>of</strong> X × are the unit group B × <strong>of</strong> the maximal order B<br />

<strong>of</strong> X.

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