Optik Moderen

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Normalisasi C dipilih sehingga medan E m(x) sesuai dengan alirandaya 1watt sepanjang sb-z.Jadi, modus E y=AE m(x) berkaitan dengan aliran daya ⎢A⎢ 2 W/m.Syarat normaliasi:r r∞∞* β= 1 ∫Re[x *] =−1m2S 2 E H dx 2 ∫ E H dx=∫[E ( x)]= 12dxzzy xmωμSubstitusi E m(x) menghasilkan:−∞−∞Cm=2hm⎧⎨⎩βm[t+ (1/ qmωμ) + (1/ pm)]( h2m+ q2m⎫⎬) ⎭1/ 2Ortonormalisasi modus-modus dituliskan:∞∫− ∞EmE*ldxωμ= 2 δβmml108
Gelombang terpandu TMHy( x,z,t)=Hm( x)ei(ω t −β z )Syarat kontinuitas H ydan E zkontinu di batas-batas lapisan.Ez=i ∂H−ωε ∂xyHm( x)=⎧ h − qx⎪−C e ,⎪ q⎪ ⎛ q ⎞⎨C⎜ cos hx − sin hx ⎟,⎪ ⎝ h ⎠⎪ ⎛ h⎞⎪−C ⎜ cos ht + sin ht ⎟ e⎪⎩⎝ q⎠p ( x + t )−,t0 ≤ x≤ x ≤ 0x ≤ − t109
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I. Gelombang EMII. Interaksi Gelomb
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Bahan optik bersifat dielektrik, is
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Gelombang bidangrErH= uˆ1= uˆE2oH
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∇.S + ∂tU= −J.E∂Ur r v r r
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2.2 Indeks bias dengan model elektr
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Tuliskan: n=n’-in”Tinjau gelomb
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2.4 Pulsa optik dan kecepatan grupD
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Dispersi materialBilangan gelombang
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3.2 Refleksi dan TransmisiTE atau g
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21Koefisien refleksi:iiixxxxxEsssnk
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23Koefisien refleksi:xxxxEpppknknkn
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3.3 Refleksi total internalk r1'k r
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Koefisien refleksi pada saat reflek
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ErH2∝=eii ( t k r2 .rω − )∇r
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Surface PlasmonReflectance10.980.96
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Dengan menggunakan syarat kontinuit
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Sistem 2-lapisan, d=0:x0n 1n 2zGel
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Komponen2 E x dan E z membentukpola
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39xzn 1n 2qxee −px[ ] cnnnnnnnncn
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41)()()()(),,(ztizztixozexHexEitzxH
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43dkidikdkixxxxxxxxdikxxxxxxerrette
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3.7 Attenuation Total Reflection (A
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Hasil-hasil perhitungan:1.41.21n 1
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10.8Reflectance0.60.4n 3 =10.2035 3
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IV. MEDIA BERLAPIS ISOTROPIK4.1 Per
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53⎟⎟⎠⎞⎜⎜⎝⎛=− 2200
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55⎟⎟⎠⎞⎜⎜⎝⎛−−−
Page 57 and 58: 4.2 Perumusan untuk Sistem Multilap
Page 59 and 60: 59⎟⎟⎠⎞⎜⎜⎝⎛⎟⎟⎠
Page 61 and 62: 61⎟⎟⎠⎞⎜⎜⎝⎛+−⎟
Page 63 and 64: V. MEDIA BERLAPIS PERIODIK 1-D5.1 M
Page 65 and 66: 65⎟⎟⎠⎞⎜⎜⎝⎛⎟⎟⎟
Page 67 and 68: 67⎥⎦⎤⎢⎣⎡⎟⎟⎠⎞⎜
Page 69 and 70: 5.2 Gelombang Bloch dan struktur pi
Page 71 and 72: ⎛⎜⎝ACB ⎞⎛a⎟⎜D ⎠⎝b
Page 73 and 74: Hubungan dispersi:eiKΛ=12( A+D)±1
Page 75 and 76: ωβ = 0gapgapgapK2π/ΛCahaya bisa
Page 77 and 78: 5.3 Reflektor BraggMedium berlapis
Page 79 and 80: TE (s); n 1=3,0 n 2=3,6 d 1=d 2=2um
Page 81 and 82: N=15, n 1=3,0 n 2=3,6 d 1=d 2=2 um1
Page 83 and 84: 10.90.8n1=1.5n2=2.5λ o=0,6 umN=30R
Page 85 and 86: 85( )[ ] 0)cos(2221222222222=+++⎥
Page 87 and 88: dA− 2iβdz2⎛ ω+⎜2⎝ cn2o22
Page 89 and 90: 89ziziaeidzdbbeidzdaδδκκ22;−=
Page 91 and 92: RκL = 10.70.60.50.40.30.20.10-15 -
Page 93 and 94: Reflektor Bragg sinusoida dengan ap
Page 95 and 96: 10.810.8γ=50.60.4Reflektans0.60.40
Page 97 and 98: 97o n onzzGnnzn
Page 99 and 100: 99)(2)()()()()(),(φδφδ−−==z
Page 101 and 102: 101Reflekror Bragg dengan chirp dan
Page 103 and 104: 7. GELOMBANG TERPANDU DALAM MEDIA B
Page 105 and 106: Gelombang terpandu TEEy( x,z,t)=Em(
Page 107: Gelombang terpandu TEn 3=3.2n 2=3.5
Page 111 and 112: 111)()(1)()]([2*]xRe[22*2121xnxdxxx
Page 113 and 114: 7.2 Sifat umum pandu gelombang diel
Page 115 and 116: Gunakan teorema Green:lim∫C→∞
Page 117 and 118: ∇2rEr2∂ E− μoε2∂ t=02 2{
Page 119 and 120: dAk iωβk*−i(βm−βk) z= −
Page 121 and 122: ∑lδβa2mml( β2l− β )rEr r*
Page 123 and 124: 7.3.2 Perturbasi dielektrik secara
Page 125 and 126: Tanda dari faktor β1 / β1dan β2/
Page 127 and 128: zn sn an sn bn sJika kedua pandugel
Page 129 and 130: 1290)()(22*)(222*22=Δ+Δ+∂∂−
Page 131 and 132: A(z)=( C1sinsz+ C2cos sz)( / 2 ) ze
Page 133 and 134: 8. OPTIK NONLINIER8.1 Pengertian No
Page 135 and 136: n≅no+χ(2)E(z,ω)2noBahan nonlini
Page 137 and 138: Modulatorφ iLdφ oVφo= φ +i= φ
Page 139 and 140: Fungsi Logika XORaPolarisasi cahaya
Page 141 and 142: 141Penguat Optik),(),(),(2(2)(1)ω
Page 143 and 144: SwitchingFebry-PerotI oI oI iI iBah
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Optik Moderen

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