Create successful ePaper yourself
Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.
1.5. teorēma. Pm(a k ) = Pm(a) tad un tikai tad, ja<br />
LKD(k, Pm(a)) = 1.<br />
PIERĀDĪJUMS No sākuma atzīmēsim, ka<br />
Pm(a k ) ≤ Pn(a),<br />
jo elementa a k pakāpju kopa ir a pakāpju kopas apakˇskopa. Ja<br />
tad no kongruences<br />
LKD(k, Pm(a)) = 1,<br />
(a k ) t ≡ a kt ≡ 1 (mod m)<br />
seko, ka Pm(a)|kt un Pm(a)|t. Tātad Pm(a k ) = Pm(a).<br />
Ja LKD(k, Pm(a)) = d = 1, tad<br />
Seko, ka Pm(a k ) = Pm(a)<br />
d<br />
(a k ) Pm(a)<br />
d ≡ (a Pm(a) ) k<br />
d ≡ 1 (mod m).<br />
< Pm(a). <br />
Saturs Sākums Beigas ◭ ◮ Atpakal¸ Aizvērt Pilns ekrāns<br />
10