MODULE 1 : GELYKTYDIGE LINEÊRE VERGELYKINGS ... - AdMaths
MODULE 1 : GELYKTYDIGE LINEÊRE VERGELYKINGS ... - AdMaths
MODULE 1 : GELYKTYDIGE LINEÊRE VERGELYKINGS ... - AdMaths
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VOORBEELD 5<br />
6 / 9<br />
Los op vir x en y: x + 3y<br />
= − 7 (1)<br />
x − y = 5 (2)<br />
As ons die vergelykings in kolomvorm aftrek, sal die veranderlike, x , kanselleer:<br />
(1) - (2)<br />
−<br />
x<br />
x<br />
.<br />
+<br />
3y<br />
− y<br />
4y<br />
x – x = 0 ; 3y – (-y) = 4y ; -7 – 5 = -12<br />
(2):<br />
Dus: x = 2 en y = − 3.<br />
VOORBEELD 6<br />
x<br />
−<br />
( −3)<br />
x<br />
=<br />
=<br />
y<br />
2<br />
A1.2<br />
5<br />
= − 7<br />
=<br />
=<br />
=<br />
5<br />
−12<br />
− 3<br />
Los op vir x en y: 5x + 2y<br />
= −1<br />
(1)<br />
4x − 2y<br />
= − 8 (2)<br />
As ons die vergelykings in kolomvorm optel, sal die veranderlike, y , kanselleer:<br />
(1) + (2)<br />
(1):<br />
⊕<br />
5(<br />
−1)<br />
Dus: x = −1<br />
en y = 2 .<br />
5x<br />
+<br />
2y<br />
4x<br />
− 2y<br />
= − 8<br />
9x<br />
. = − 9<br />
+<br />
2y<br />
2y<br />
y<br />
=<br />
=<br />
=<br />
x<br />
4<br />
2<br />
= −1<br />
=<br />
−1<br />
−1