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75. What are the advantages and disadvantages of convolutional codes?<br />

76. Explain about the Viterbi decoding method with an example.<br />

77. (a) What is meant by random errors and burst errors? Explain about a coding<br />

technique which can be used to correct both the burst and random errors simultaneously.<br />

(b) Discuss about the various decoders for convolutional codes.<br />

78. Draw the state diagram, tree diagram for K=3, rate1/3 code generated by<br />

79. (a) Design an encoder for the (7,4) binary cyclic code generated by g(x) = 1+x+x 3 and verify its<br />

operation using the message vector (0101).<br />

(b) What are the differences between block codes and the convolutional codes?<br />

80. Explain various methods for describing Conventional Codes.<br />

81. A convolutional encoder has two shift registers two modulo-2 adders and an output multiplexer.<br />

The generator sequences of the encoder are as follows: g (1) =(1,0,1); g (2) =( 1,1, 1). Assuming a<br />

5bit message sequence is transmitted. Using the state diagram find the message sequence when<br />

the received sequence is<br />

(11,01,00,10,01,10,11,00,00,......)<br />

82. (a) What is meant by random errors and burst errors? Explain about a coding technique which<br />

can be used to correct both the burst and random errors simultaneously.<br />

(b) Discuss about the various decoders for convolutional codes.<br />

83. Find the output codeword for the following convolutional encoder for the message sequence<br />

10011. (as shown in the figure).<br />

84. Construct the state diagram for the following encoder. Starting with all zero state, trace the path<br />

that correspond to the message sequence 1011101. Given convolutional encoder has a single shift<br />

register with two stages,(K=3) three modulo-2 adders and an output multiplexer. The generator<br />

sequence s of the encoder are as follows. g(1)=(1, 0, 1) ; g(2)=(1, 1, 0),g(3)=(1,1,1).<br />

85. Draw and explain Tree diagram of convolutional encoder shown below with rate=1/3, L=3

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