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Asymptotic Analysis and Singular Perturbation Theory

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=<br />

Rd <br />

− 2<br />

<br />

∆u + V u v dx<br />

2m<br />

= 〈Hu, v〉.<br />

Thus, this operator is formally self-adjoint. Under suitable conditions on the potential<br />

V , the operator can be shown to be self-adjoint with respect to an appropriately<br />

chosen domain.<br />

Now suppose that the potential V ε depends on a parameter ε, <strong>and</strong> has the<br />

expansion<br />

V ε (x) = V0(x) + εV1(x) + O(ε 2 ).<br />

The perturbation in a simple energy eigenvalue<br />

assuming one exists, is given by<br />

E ε = E0 + εE1 + O(ε 2 ),<br />

E1 =<br />

<br />

Rd V1(x)|ϕ0(x)| 2 dx<br />

<br />

Rd |ϕ0(x)| 2 ,<br />

dx<br />

where ϕ0 ∈ L 2 (R d ) is an unperturbed energy eigenfunction that satisfies<br />

− 2<br />

2m ∆ϕ0 + V0ϕ0 = E0ϕ0.<br />

Example 1.7 The one-dimensional simple harmonic oscillator has potential<br />

The eigenvalue problem<br />

V0(x) = 1<br />

2 kx2 .<br />

− 2<br />

2m ϕ′′ + 1<br />

2 kx2 ϕ = Eϕ, ϕ ∈ L 2 (R)<br />

is exactly solvable. The energy eigenvalues are<br />

<br />

En = ω n + 1<br />

<br />

n = 0, 1, 2, . . . ,<br />

2<br />

where<br />

ω =<br />

k<br />

m<br />

is the frequency of the corresponding classical oscillator. The eigenfunctions are<br />

ϕn(x) = Hn(αx)e −α2 x 2 /2 ,<br />

where Hn is the nth Hermite polynomial,<br />

Hn(ξ) = (−1) n dn ξ2<br />

e e−ξ2,<br />

dξn 11

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