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Asymptotic Analysis and Singular Perturbation Theory

Asymptotic Analysis and Singular Perturbation Theory

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Chapter 3<br />

<strong>Asymptotic</strong> Expansion of Integrals<br />

In this chapter, we give some examples of asymptotic expansions of integrals. We<br />

do not attempt to give a complete discussion of this subject (see [4], [21] for more<br />

information).<br />

3.1 Euler’s integral<br />

Consider the following integral (Euler, 1754):<br />

I(x) =<br />

∞<br />

0<br />

e−t dt, (3.1)<br />

1 + xt<br />

where x ≥ 0.<br />

First, we proceed formally. We use the power series expansion<br />

1<br />

1 + xt = 1 − xt + x2 t 2 + . . . + (−1) n x n t n + . . . (3.2)<br />

inside the integral in (3.1), <strong>and</strong> integrate the result term-by-term. Using the integral<br />

we get<br />

∞<br />

t<br />

0<br />

n e −t dx = n!,<br />

I(x) ∼ 1 − x + 2!x 2 + . . . + (−1) n n!x n + . . . . (3.3)<br />

The coefficients in this power series grow factorially, <strong>and</strong> the terms diverge as n →<br />

∞. Thus, the series does not converge for any x = 0. On the other h<strong>and</strong>, the<br />

following proposition shows that the series is an asymptotic expansion of I(x) as<br />

x → 0 + , <strong>and</strong> the the error between a partial sum <strong>and</strong> the integral is less than the<br />

first term neglected in the asymptotic series. The proof also illustrates the use of<br />

integration by parts in deriving an asymptotic expansion.<br />

29

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