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Asymptotic Analysis and Singular Perturbation Theory

Asymptotic Analysis and Singular Perturbation Theory

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with the substrate is balanced by the destruction of the complex by the reverse<br />

reaction <strong>and</strong> the decomposition of the complex into the product <strong>and</strong> the enzyme.<br />

Substituting this result into the first equation, we get a first order ODE for u0(τ):<br />

du0<br />

dτ<br />

The solution of this equation is given by<br />

= − λu0<br />

u0 + k .<br />

u0(τ) + k log u0(τ) = a − λτ,<br />

where a is a constant of integration. This solution is invalid near τ = 0 because no<br />

choice of a can satisfy the initial conditions for both u0 <strong>and</strong> v0.<br />

4.1.2 Inner solution<br />

There is a short initial layer, for times t = O(ε), in which u, v adjust from their<br />

initial values to values that are compatible with the outer solution found above. We<br />

introduce inner variables<br />

The inner equations are<br />

We look for an innner expansion<br />

T = τ<br />

, U(T, ε) = u(τ, ε), V (T, ε) = v(τ, ε).<br />

ε<br />

The leading order inner equations are<br />

The solution is<br />

dU<br />

= ε {−U + (U + k − λ)V } ,<br />

dT<br />

dV<br />

= U − (U + k)V,<br />

dT<br />

U(0, ε) = 1, V (0, ε) = 0.<br />

U(T, ε) = U0(T ) + εU1(T ) + O(ε 2 ),<br />

V (T, ε) = V0(T ) + εV1(T ) + O(ε 2 ).<br />

dU0<br />

= 0,<br />

dT<br />

dV0<br />

dT = U0 − (U0 + k)V0,<br />

U0(0) = 1, V0(0) = 0.<br />

U0 = 1,<br />

V0 = 1<br />

<br />

<br />

−(1+k)T<br />

1 − e .<br />

1 + k<br />

52

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