Asymptotic Analysis and Singular Perturbation Theory
Asymptotic Analysis and Singular Perturbation Theory
Asymptotic Analysis and Singular Perturbation Theory
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with the substrate is balanced by the destruction of the complex by the reverse<br />
reaction <strong>and</strong> the decomposition of the complex into the product <strong>and</strong> the enzyme.<br />
Substituting this result into the first equation, we get a first order ODE for u0(τ):<br />
du0<br />
dτ<br />
The solution of this equation is given by<br />
= − λu0<br />
u0 + k .<br />
u0(τ) + k log u0(τ) = a − λτ,<br />
where a is a constant of integration. This solution is invalid near τ = 0 because no<br />
choice of a can satisfy the initial conditions for both u0 <strong>and</strong> v0.<br />
4.1.2 Inner solution<br />
There is a short initial layer, for times t = O(ε), in which u, v adjust from their<br />
initial values to values that are compatible with the outer solution found above. We<br />
introduce inner variables<br />
The inner equations are<br />
We look for an innner expansion<br />
T = τ<br />
, U(T, ε) = u(τ, ε), V (T, ε) = v(τ, ε).<br />
ε<br />
The leading order inner equations are<br />
The solution is<br />
dU<br />
= ε {−U + (U + k − λ)V } ,<br />
dT<br />
dV<br />
= U − (U + k)V,<br />
dT<br />
U(0, ε) = 1, V (0, ε) = 0.<br />
U(T, ε) = U0(T ) + εU1(T ) + O(ε 2 ),<br />
V (T, ε) = V0(T ) + εV1(T ) + O(ε 2 ).<br />
dU0<br />
= 0,<br />
dT<br />
dV0<br />
dT = U0 − (U0 + k)V0,<br />
U0(0) = 1, V0(0) = 0.<br />
U0 = 1,<br />
V0 = 1<br />
<br />
<br />
−(1+k)T<br />
1 − e .<br />
1 + k<br />
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