Asymptotic Analysis and Singular Perturbation Theory
Asymptotic Analysis and Singular Perturbation Theory
Asymptotic Analysis and Singular Perturbation Theory
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3.2 Perturbed Gaussian integrals<br />
Consider the following integral<br />
I(a, ε) =<br />
∞<br />
−∞<br />
<br />
exp − 1<br />
2 ax2 − εx 4<br />
<br />
dx, (3.4)<br />
where a > 0 <strong>and</strong> ε ≥ 0. For ε = 0, this is a st<strong>and</strong>ard Gaussian integral, <strong>and</strong><br />
I(a, 0) = 1<br />
√ 2πa .<br />
For ε > 0, we cannot compute I(a, ε) explicitly, but we can obtain an asymptotic<br />
expansion as ε → 0 + .<br />
First, we proceed formally. Taylor exp<strong>and</strong>ing the exponential with respect to ε,<br />
<br />
exp − 1<br />
2 ax2 − εx 4<br />
<br />
1 −<br />
= e 2 ax2<br />
<br />
1 − εx 4 + 1<br />
2! ε2x 8 + . . . + (−1)n<br />
ε<br />
n!<br />
n x 4n <br />
+ . . . ,<br />
<strong>and</strong> integrating the result term-by-term, we get<br />
I(a, ε) ∼ 1<br />
<br />
√<br />
2πa<br />
where<br />
1 − ε〈x 4 〉 + . . . + (−1)n<br />
ε<br />
n!<br />
n 〈x 4n 〉 + . . .<br />
〈x 4n 〉 =<br />
∞<br />
−∞ x4n 1 − e 2 ax2<br />
∞ 1<br />
e− 2<br />
−∞ ax2<br />
dx<br />
dx .<br />
We use a special case of Wick’s theorem to calculate these integrals.<br />
Proposition 3.3 For m ∈ N, we have<br />
where<br />
Proof. Let<br />
〈x 2m 〉 =<br />
(2m − 1)!!<br />
am ,<br />
(2m − 1)!! = 1 · 3 · 5 . . . (2m − 3) · (2m − 1).<br />
J(a, b) =<br />
∞ 1<br />
e− 2<br />
−∞ ax2 +bx dx<br />
∞ 1<br />
e− 2<br />
−∞ ax2 dx .<br />
<br />
, , (3.5)<br />
Differentiating J(a, b) n-times with respect to b <strong>and</strong> setting b = 0, we find that<br />
〈x n 〉 = dn<br />
<br />
<br />
J(a, b) .<br />
dbn Writing<br />
b=0<br />
1 −<br />
e 2 ax2 +bx −<br />
= e 1<br />
2 a(x−b)2 + b2<br />
2a<br />
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