Jasmone 1 - ChemistforChrist
Jasmone 1 - ChemistforChrist
Jasmone 1 - ChemistforChrist
Create successful ePaper yourself
Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.
Synthesis of JASMONE<br />
O<br />
O<br />
DIBAL-H<br />
For a lactone the best<br />
reducing agent to a lactole<br />
is DIBAL-H, for an ester this<br />
might not work so well!<br />
H<br />
OH<br />
O<br />
Thermodynamically more<br />
stable due to being<br />
a trisubstituted double<br />
bond.<br />
O<br />
under the acidc<br />
conditions:<br />
isomerization<br />
MeLi<br />
Me<br />
<strong>Jasmone</strong><br />
O<br />
O<br />
OH<br />
More resources available at<br />
www.chemistforchrist.de<br />
OH<br />
O<br />
CrO 3, verd. H 2SO 4, Aceton<br />
Jones-Reagent<br />
Me CrO3, verd. H2SO4, Aceton<br />
OH<br />
Jones-Reagent<br />
CrO 3<br />
HO<br />
tertiary alcohol,<br />
H 2O is eliminated<br />
Wittig<br />
tertiary alcohol cannot be oxidized!<br />
The textbook Clayden, Greeves, Warren and Wothers (Oxford University press, p. 951, 2004 reprint) proposes<br />
a different mechanism:<br />
OH (VI)<br />
OH<br />
O<br />
R Li<br />
R<br />
O<br />
CrO3 R (VI)<br />
CrO<br />
orange<br />
3<br />
OH<br />
R CrO 3<br />
H<br />
O OH<br />
Cr<br />
O O<br />
R<br />
H<br />
[3,3]<br />
HO OH<br />
Cr<br />
O O<br />
H<br />
H R<br />
Me<br />
O<br />
(III)<br />
CrO3 R<br />
+ Cr(IV)<br />
green<br />
PPh 3<br />
OH<br />
Me<br />
Me<br />
gives Cr(III) and Cr(VI)<br />
by disproportionation.<br />
The first step is the formation of a chromate ester but this intermediate has no proton to lose, so it transfers<br />
the chromate to the other end of the allylic system where there is a proton. The chromate transfer can be<br />
drawn as a [3,3] sigmatropic rearrangement.<br />
Very general method:<br />
R' MgBr<br />
O<br />
R<br />
HO<br />
R'<br />
R'<br />
R H<br />
R<br />
OH<br />
Ox<br />
R'<br />
R<br />
O