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Commutative algebra - Department of Mathematical Sciences - old ...

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12 1. A DICTIONARY ON RINGS AND IDEALS<br />

1.2.9. Proposition. Let φ : R → S be a ring homomorphism.<br />

(1) Let I ⊂ Ker φ be an ideal. Then there is a unique ring homomorphism<br />

φ ′ : R/I → S such that φ = φ ′ ◦ π.<br />

R<br />

π<br />

<br />

R/I<br />

φ<br />

(2) The homomorphism φ ′ : R/ Ker φ → S is a ring isomorphism onto the<br />

subring φ(R) <strong>of</strong> S.<br />

R<br />

π<br />

<br />

R/ Ker φ<br />

φ<br />

φ ′<br />

φ ′<br />

<br />

<br />

S<br />

<br />

φ(R)<br />

<br />

(3) For any ideal J ⊂ S, I = φ −1 (J) ⊂ R is an ideal and the map φ ′ : R/I →<br />

S/J is an injective ring homomorphism.<br />

Pro<strong>of</strong>. The statements are clear for the addition and the factor map φ ′ (a + I) =<br />

φ(a) is clearly a ring homomorphism.<br />

1.2.10. Corollary. Let π : R → R/I be the projection. The map I ′ ↦→ J =<br />

π −1 (I ′ ) gives a bijective correspondence between ideals I ′ in R/I and ideals J in<br />

R containing I. Also I ′ = π(J) = J/I. This correspondence preserves inclusions,<br />

sums and intersections <strong>of</strong> ideals.<br />

1.2.11. Corollary. Let I ⊂ J ⊂ R be ideals. Then there is a canonical isomorphism<br />

R/J → (R/I)/(J/I)<br />

Pro<strong>of</strong>. The kernel <strong>of</strong> the surjective east-south composite<br />

R<br />

<br />

R/J<br />

<br />

R/I<br />

<br />

<br />

(R/I)/(J/I)<br />

is J. By 1.2.9 the horizontal lower factor map gives the isomorphism.<br />

1.2.12. Example. For any integer n the ideals in the factor ring Z/(n) correspond<br />

to ideals (m) ⊂ Z where m divides n.<br />

1.2.13. Definition. Let R be a ring. The additive kernel <strong>of</strong> the unique ring homomorphism<br />

Z → R is a principal ideal generated by a natural number char(R), the<br />

characteristic <strong>of</strong> R. Z/(char(R)) is isomorphic to the smallest subring <strong>of</strong> R.<br />

1.2.14. Proposition. If the characteristic char(R) = p is a prime number, then<br />

the Frobenius homomorphism R → R, a ↦→ a p is a ring homomorphism.<br />

Pro<strong>of</strong>. By the binomial formula 1.1.4<br />

(a + b) p p<br />

<br />

p<br />

=<br />

k<br />

k=0<br />

a p−k b k = a p + b p

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