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PHYS01200804001 Sohrab Abbas - Homi Bhabha National Institute

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We shall confine our discussion henceforth to nonabsorbing centrosymmetric crystals, for the sake<br />

of simplicity and clarity. The assumption of zero absorption is fairly accurate for instance, with<br />

crystals of silicon which exhibit absorption lengths of a few metres for Å wavelength neutrons. The<br />

quantities O , H (=– H ), K, K O and K H are thus all real.<br />

The internal wave solutions can then be represented by<br />

1 y<br />

ψ<br />

Oα<br />

= 1- ψ<br />

Oβ<br />

= 1-<br />

<br />

<br />

2<br />

2<br />

y +1<br />

<br />

<br />

<br />

1 | b | <br />

and ψ<br />

Hα<br />

= -ψ<br />

Hβ<br />

= - ,<br />

2 2<br />

y +1 <br />

<br />

(30)<br />

with the associated wave vector magnitudes<br />

k χ | b |<br />

Oα<br />

β<br />

K = K ±<br />

0 H<br />

2<br />

y +1 ± y<br />

2<br />

k0χ<br />

H<br />

K<br />

Hα<br />

= K ±<br />

β<br />

<br />

2<br />

y +1 y .<br />

2 | b |<br />

<br />

<br />

(31)<br />

For incidence at θ = θ C , i.e. y = 0, the incident wave splits equally into the α and β waves. ψ Oβ gets<br />

stronger at the expense of ψ Oα , as θ increases beyond θ C (y >0), whereas ψ Oα becomes the dominant<br />

component on the other side of θ C . The diffracted wave amplitudes on the other hand exhibit a<br />

peak,<br />

| b | / 2 in magnitude, at θ C and fall symmetrically on both sides of θ C . The diffracted<br />

intensities<br />

2<br />

<br />

H<br />

and 2 H<br />

drop to half their peak values at y = ±1, corresponding to an FWHM equal<br />

to w i of Eq.(22). Thus θ C represents the centre of diffraction in the Laue case as well. Only in the<br />

symmetric Laue configuration, does θ C equal θ B represented by the point L, the centre of<br />

diffraction within the kinematical model.<br />

26

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