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CHEM01200604012 Dibakar Goswami - Homi Bhabha National ...

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It has also been reported, 83a,b that in acidic conditions, there is equilibrium such as<br />

2In (s) + 2 In +3 = 3 In +1 . Given that [bmim][Br] is acidic (pH = 5.78), such an equilibrium<br />

exists in the acidic protic ionic liquid. Therefore, InBr was formed in the reaction mixture.<br />

The resultant InBr would then react with allyl bromide to furnish the active species II (eq.<br />

5). Hence, there are two competitive pathways for the formation of II, viz. (i) formation of<br />

II from activated In metal (Scheme II.3.5, eq. 1), and (ii) formation of II via oxidation of<br />

In metal and subsequent reaction with allyl bromide (Scheme II.3.5, eq. 3-5).<br />

1 / 4 In + 1 / 2<br />

Br 1 / InBr 2 4<br />

+ 1 / 4<br />

.<br />

+ [bmim][Br] Br<br />

.<br />

+ 1 / 4 [bmim] .<br />

(1)<br />

(2)<br />

1 / 1 4<br />

/ 1 4<br />

/ 4 1 / 4 In + 3 / 4 [bmim]Br 1/ 4 InBr 3 + 3 / 4 [bmim] .<br />

(3)<br />

1 / 4 InBr 3 + 1 / 2 In 3 / 4 InBr<br />

(4)<br />

3 / 4 InBr + 3 Br 3 InBr 2<br />

/ 4<br />

/ 4<br />

(5)<br />

InBr 2<br />

+ RCHO<br />

R<br />

OInBr 2<br />

(6)<br />

R<br />

OInBr 2<br />

+ H 2 0 + [bmim][Br]<br />

R<br />

OH<br />

+ [bmim][OH] + InBr 3 (7)<br />

Total reaction :<br />

In + 2[bmim][Br] + RCHO +<br />

Br + H2 O<br />

R<br />

OH<br />

+ InBr 3 + [bmim][OH] + [bmim]<br />

(8)<br />

Scheme II.3.5<br />

52

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