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Multiattribute acceptance sampling plans - Library(ISI Kolkata ...

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From (2.3.2) we observe that<br />

γ<br />

2<br />

1<br />

g ( k , m'<br />

γ g ( k , m<br />

( r −1)<br />

( r −1)<br />

) g (0, m'<br />

)<br />

) g<br />

( 0, m)<br />

)<br />

><br />

γ<br />

γ<br />

2<br />

1<br />

− ( m ′− m )<br />

e<br />

k + 1 ≥<br />

[ m′<br />

/ m]<br />

1<br />

This implies , RD (n; k) > RA (n; a 1 = k-1,..., a r-1 = k-1, a r = k). (Proved)<br />

Remarks:<br />

A. The condition (2.3.1) is a sufficient condition and holds if<br />

( p ′ / p′<br />

) < ( p / p )<br />

r<br />

( r−1)<br />

r<br />

( r −1)<br />

B. For r = 2 the condition (2.3.1) becomes<br />

(<br />

p<br />

k<br />

k + 1<br />

′<br />

1<br />

/ p<br />

1<br />

) > ( p ′ / p )<br />

For r = 2 this implies<br />

p<br />

′<br />

p<br />

1<br />

><br />

1<br />

.<br />

p′<br />

p<br />

We now try to obtain more general results.<br />

2.3.3 Situation 2<br />

Let us consider the set of A <strong>plans</strong> with <strong>acceptance</strong> criteria<br />

x ≤ a for i = 1, 2,..., r-1<br />

x<br />

( i ) r − 1<br />

( r )<br />

≤ a r<br />

.<br />

Note that the probability of <strong>acceptance</strong> at a process average p = ( p1 ,..., pr<br />

) for this plan is<br />

PA ( a1 , a<br />

2<br />

,..., a<br />

r<br />

; m1<br />

, m<br />

2 ,...,mr<br />

) =<br />

a a −x<br />

r<br />

= ∑ − 1 r ( r<br />

.... ∑ − 1) r<br />

∏ g(<br />

x i<br />

, m i<br />

)<br />

x = x = 0 i=<br />

1<br />

1<br />

0<br />

r<br />

a<br />

r<br />

∑ − 1<br />

= g ( x( r − ),<br />

m<br />

x( r )<br />

− 1<br />

= 0<br />

ar<br />

− x<br />

1 ( r −1)<br />

) ∑<br />

x = 0<br />

r<br />

( r−1)<br />

( x r<br />

, m r<br />

)<br />

g ... (2.3.3)<br />

Theorem (2.3.2)<br />

Let n, a r-1 , a r be the optimal parameters with <strong>acceptance</strong> criterion specified at the beginning<br />

of the section 2.3.4, for a given lot size N, γ 1 , γ 2 , p, p' etc. and assumption a r-1 ≥ 1. If we<br />

now construct a plan with the same sample size but with <strong>acceptance</strong> criterion changed to:<br />

x ( r − 2 )<br />

≤ a<br />

r − 1<br />

− 1 , x(<br />

r − 1)<br />

≤ a<br />

r −1<br />

, x(<br />

r )<br />

≤ a<br />

r then the latter plan will have lesser<br />

regret value than the former plan, optimal in the specified set up, if<br />

′ r −1<br />

[ ( r −2<br />

)<br />

p( r −2<br />

) / p<br />

]<br />

a<br />

> [ p ′<br />

( r −1)<br />

/ p<br />

( r −1)<br />

]<br />

a r −1<br />

+ 1<br />

... (2.3.4)<br />

96

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