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Multiattribute acceptance sampling plans - Library(ISI Kolkata ...

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easonable to assume that the p i ’s are independently distributed in the present context.<br />

It should be pointed out at this stage that the beta and gamma distribution are, however,<br />

not always appropriate. For example, we could not fit the gamma or beta distribution in<br />

case of quality variation of ceiling fans, garments and cigarettes the relevent data on which<br />

were collected. In such cases we will have to take recourse to direct computation of the cost<br />

function derived from the empirical distributions as observed. Numerically, the difficulty<br />

level in computation will not increase significantly. Nevertheless, since the gamma (or beta )<br />

distribution is likely to be appropriate at least in some situations and neat theoretical expressions<br />

can be obtained in such cases, we will study the cost functions under such assumptions.<br />

3.1.5 The expression of average costs under the assumption of independent<br />

gamma prior distributions of the process average vector<br />

Theorem 3.1.1<br />

Let each p i be distributed with probability density function f(p i , ¯p i , s i ) for i = 1, 2, ..., r;<br />

p i ’s are jointly independent; the lot quality X i is distributed as g(X i , Np i ) ∀i and X i ’s are<br />

jointly independent. The optimal plan in this situation for a specified <strong>acceptance</strong> criteria<br />

x = (x 1 , x 2 , ..., x r ) ∈ A is obtained by minimizing the function :<br />

[ { ∑ r∑<br />

} r∏<br />

K(N, n)/(A 1 −R 1 ) = nk s+(N−n)k ′ r+(N−n)<br />

′ d i ¯p i (s i + x i )/(s i + n ¯p i ) − d 0 g(x i , n ¯p i , s i )<br />

x∈A i=1<br />

i=1<br />

where g(x i , n ¯p i , s i ) is a gamma-Poisson density given by,<br />

g(x i , n ¯p i , s i ) = Γ(s i + x i )<br />

θ s i<br />

i .(1 − θ i ) x i<br />

; θ i =<br />

x!Γs<br />

and x i non-negative integer. k ′ s = k s /(A 1 − R 1 ), k ′ r = k r /(A 1 − R 1 ).<br />

s i<br />

(s i + n ¯p i )<br />

...(3.1.7)<br />

Proof:<br />

Since,<br />

∫ ∫ r∏<br />

r∏<br />

... p i g(x j , np j )f(p j , ¯p j , s j )dp j = [ ¯p i (s i + x i )/(s i + n ¯p i ) g(x j , n ¯p j , s j )<br />

∫p 1 p 2 p r j=1<br />

j=1<br />

We get,<br />

∫ ∫<br />

... d i p i P (p)dw(p 1 )dw(p 2 )..dw(p r ) =<br />

∫p ∑ r∏<br />

d i ¯p i (s i + x i )/(s i + n ¯p i ) g(x i , n ¯p i , s i ).<br />

1 p 2 p r x∈A<br />

i=1<br />

126<br />

]

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