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Computer Tools for Bifurcation Analysis: General Approach with

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<strong>Computer</strong> <strong>Tools</strong> <strong>for</strong> <strong>Bifurcation</strong> <strong>Analysis</strong> 991<br />

The coefficient in Eq. (26) λ 1 = c 2, 2 (R 1 )/c 2, 1 .<br />

Formulae <strong>for</strong> calculation of coefficients c are given<br />

by the set of the replacement rules:<br />

{c[2, 1] -> Ut . U,<br />

c[2, 2][R[1]] -> Ut . f (1,1) [u, R] . U .<br />

R[1]}.<br />

The second equation is a well-known Landau equation,<br />

and the coefficient at the nonlinear term ν 0 =<br />

c 3, 2 /c 3, 1 is called the Landau coefficient. The sign<br />

of this coefficient determines the type of the bifurcation<br />

— the subcritical one <strong>with</strong> unstable limit cycle<br />

coefficient arises if the real part of the coefficient is<br />

positive, and the supercritical otherwise. The unnormalized<br />

Landau coefficient c 3,2 is produced by<br />

the function in the following <strong>for</strong>m:<br />

c[3, 2] -> -Ut . f (2,0) [u, R] . U .<br />

LinearSolve[f (1,0) [u, R], f (2,0) [u, R] .<br />

DiracConjugate[U] . U] -<br />

Ut . f (2,0) [u, R] . DiracConjugate[U] .<br />

LinearSolve[-2 I w IdentityTensor[2] +<br />

f (1,0) [u, R],<br />

f (2,0) [u, R] . U . U] / 2 +<br />

Ut . f (3,0) [u, R] . DiracConjugate[U] . U .<br />

U / 2,<br />

and can be written in the standard notation as:<br />

c 3, 2 = −U † f uu UR(f u )f uu UŨ<br />

− U † f uu ŨR(−2iwI + f u )f uu UU/2<br />

− U † f uuu UUŨ/2 , (34)<br />

where I denotes the identity matrix, which<br />

corresponds to the IdentityTensor[2] (tensor<br />

of the rank 2) generated by the function<br />

<strong>Bifurcation</strong>Theory. The R(m) denotes the resolvent<br />

matrix of the matrix m — if the matrix is<br />

regular, resolvent coincides <strong>with</strong> the inverse matrix,<br />

otherwise, resovent is constructed using the spectrum<br />

of the original matrix m. A special function<br />

Resolvent[matrix] is designed <strong>for</strong> the construction<br />

of the resolvent of a singular matrix.<br />

Finally the linear term coefficient in the Landau<br />

equation depends on parametric deviations of<br />

the first- and second-order:<br />

c 3, 3 (R 1 , R 2 )<br />

=(U † R(−iwI+f u )f uR UR 1 )(U † f uR UR 1 )/(U † U)<br />

+ U † f uR UR 2 −U † f uR R(−iwI+f u )f uR UR 1 R 1<br />

+ U † f uRR UR 1 R 1 /2 . (35)<br />

It can be easily seen that the condition R 1 = 0<br />

reduces the above general expression to linear coefficient<br />

λ 2 in (31) depending on R 2 only.<br />

The case of a monotonic bifurcation is more<br />

complicated, the resulting <strong>for</strong>mulae are more cumbersome,<br />

and we present the results of the Mathematica<br />

calculations in the standard notation. It<br />

must be noted that it has been indicated in the<br />

previous section that the first-order parametric deviation<br />

R 1 is automatically set to zero.<br />

The set of two amplitude equations describing<br />

the slow dynamics of the amplitude a now takes a<br />

<strong>for</strong>m:<br />

∂ 1 a = c 2, 2<br />

c 2, 1<br />

a 2 + c 2, 3(R 2 )<br />

c 2, 1<br />

,<br />

∂ 2 a = c 3, 2<br />

c 3,, 1<br />

a 3 + c 3, 3(R 2 )<br />

c 3, 1<br />

a + c 3, 4(R 3 )<br />

c 3, 1<br />

.<br />

(36)<br />

Now the nontrivial amplitude equation appears<br />

already at the first time scale t 1 . It contains<br />

quadratic in amplitude term <strong>with</strong> unnormalized coefficient<br />

given by:<br />

c 2, 2 = U † f uu UU/2 , (37)<br />

and corresponds to µ 0 in (12); the coefficient c 2, 3<br />

coincides <strong>with</strong> κ 2 in (12).<br />

The equation at the slower time scale gives corrections<br />

to the principal equation. Its Landau coefficient<br />

can be cast as follows:<br />

c 3, 2 =(U † R(f u )f uu UU)(U † f uu UU)/(2U † U)<br />

− U † f uu UR(f u )f uu UU/2<br />

+ U † f uuu UUU/6 . (38)<br />

The linear term coefficient is given as:<br />

c 3, 3 (R 2 )<br />

= U † f uR UR 2<br />

+(U † R(f u )f uu UU)(U † f uR UR 2 )/(U † U)<br />

− U † f uu UR(f u )f R R 2 .<br />

(39)<br />

Finally the free term in the equation coincides <strong>with</strong><br />

κ 3 in (19).

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