Advanced Abstract Algebra - Maharshi Dayanand University, Rohtak
Advanced Abstract Algebra - Maharshi Dayanand University, Rohtak
Advanced Abstract Algebra - Maharshi Dayanand University, Rohtak
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UNIT-IV<br />
77<br />
A. B ≠ B. A.<br />
If IR, the set of real numbers is replaced by E, the set of even integers, then<br />
(M 2<br />
(E), + ;) is a non-commutative ring without identity, as<br />
4. Z 4<br />
: Set of integers module 4.<br />
is a commutative ring with identity<br />
, where +, ; are defined shown in following tables:<br />
In bZ<br />
bbg<br />
= m<br />
g r r<br />
Important Remark:<br />
. 4 0 1 2 3<br />
0 0 0 0 0<br />
1 0 1 2 3<br />
2 0 2 0 2<br />
3 0 3 2 1<br />
As we saw in a group that Cancellation law holds but in a ring the cancellation law may fail for multiplication:<br />
g<br />
6<br />
, + , . , 2. 3 = 0 = 4. 3 but 2 ≠4.<br />
∉ E. F B A<br />
,<br />
H G I K J Definition F H G I K J Subring:<br />
b 0 0 1 F =<br />
H G<br />
0 0 I φZ ≠+ o<br />
K J<br />
4 :, S, 4 + ∈, 1R ;<br />
2 1 , b3<br />
∈,<br />
R3<br />
∀ a,<br />
b ∈R<br />
1 a 4∃<br />
u ~ −<br />
S . ∈<br />
b<br />
1<br />
= 0∈L<br />
R<br />
= 0R<br />
−<br />
ab0, = 2, , a4 4. 1 20 = 2b, 4=<br />
. 04 = 4.<br />
0 0 112 0 Let (R,<br />
3 0 0+, .) is a ring 1 0and<br />
a non-empty subset of R. Then bS, + , . g(with same binary operations) is called<br />
a subring if<br />
1 1 2 3 0<br />
1. Closure<br />
2 2 3 0 1<br />
3 3 0 1 2<br />
2. ∀ a ∈ R, − a∈R.<br />
Examples:<br />
(1) bZ 6<br />
, + ,. gis a commutative ring with identity.<br />
(S, +, .) is a subring with identity (multiplicative)<br />
, since<br />
Note that parent ring Z 6 , + ; ghas identity . This shows that a<br />
subring may have a different identity from that of a given ring.<br />
Definitions: Units in a ring<br />
Let R be a commutative righ with identity 1. An element a<br />
that a.b = l. The element a<br />
Divisiors of Zero<br />
If and ab = 0 for some non zero<br />
universe of a (if it exists)<br />
∈ R is called a Unit of R.<br />
b<br />
∈ R is said to be invertible if<br />
such<br />
. Then ‘a’ cannot be unit in R, since multiplying ab = 0, by the