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Advanced Abstract Algebra - Maharshi Dayanand University, Rohtak

Advanced Abstract Algebra - Maharshi Dayanand University, Rohtak

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UNIT-IV<br />

77<br />

A. B ≠ B. A.<br />

If IR, the set of real numbers is replaced by E, the set of even integers, then<br />

(M 2<br />

(E), + ;) is a non-commutative ring without identity, as<br />

4. Z 4<br />

: Set of integers module 4.<br />

is a commutative ring with identity<br />

, where +, ; are defined shown in following tables:<br />

In bZ<br />

bbg<br />

= m<br />

g r r<br />

Important Remark:<br />

. 4 0 1 2 3<br />

0 0 0 0 0<br />

1 0 1 2 3<br />

2 0 2 0 2<br />

3 0 3 2 1<br />

As we saw in a group that Cancellation law holds but in a ring the cancellation law may fail for multiplication:<br />

g<br />

6<br />

, + , . , 2. 3 = 0 = 4. 3 but 2 ≠4.<br />

∉ E. F B A<br />

,<br />

H G I K J Definition F H G I K J Subring:<br />

b 0 0 1 F =<br />

H G<br />

0 0 I φZ ≠+ o<br />

K J<br />

4 :, S, 4 + ∈, 1R ;<br />

2 1 , b3<br />

∈,<br />

R3<br />

∀ a,<br />

b ∈R<br />

1 a 4∃<br />

u ~ −<br />

S . ∈<br />

b<br />

1<br />

= 0∈L<br />

R<br />

= 0R<br />

−<br />

ab0, = 2, , a4 4. 1 20 = 2b, 4=<br />

. 04 = 4.<br />

0 0 112 0 Let (R,<br />

3 0 0+, .) is a ring 1 0and<br />

a non-empty subset of R. Then bS, + , . g(with same binary operations) is called<br />

a subring if<br />

1 1 2 3 0<br />

1. Closure<br />

2 2 3 0 1<br />

3 3 0 1 2<br />

2. ∀ a ∈ R, − a∈R.<br />

Examples:<br />

(1) bZ 6<br />

, + ,. gis a commutative ring with identity.<br />

(S, +, .) is a subring with identity (multiplicative)<br />

, since<br />

Note that parent ring Z 6 , + ; ghas identity . This shows that a<br />

subring may have a different identity from that of a given ring.<br />

Definitions: Units in a ring<br />

Let R be a commutative righ with identity 1. An element a<br />

that a.b = l. The element a<br />

Divisiors of Zero<br />

If and ab = 0 for some non zero<br />

universe of a (if it exists)<br />

∈ R is called a Unit of R.<br />

b<br />

∈ R is said to be invertible if<br />

such<br />

. Then ‘a’ cannot be unit in R, since multiplying ab = 0, by the

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