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Advanced Abstract Algebra - Maharshi Dayanand University, Rohtak

Advanced Abstract Algebra - Maharshi Dayanand University, Rohtak

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UNIT-I<br />

25<br />

1<br />

Note that αβ = <br />

2<br />

2<br />

1<br />

3<br />

1<br />

≠ <br />

3<br />

3<br />

2<br />

2<br />

3<br />

<br />

1<br />

= βα<br />

Hence S<br />

3<br />

, the group of 6 elements, called symmetric group which is non-abelian. This is the smallest finite<br />

non-abelian group, since groups of order 1, 2, 3, 5 are of prime order, hence cyclic and, therefore, they<br />

are abelian. A group of order 4 is of two types upto isomophism, either cyclic or Klein 4-group, given in<br />

example 2.<br />

Cycle Notation<br />

1<br />

2 3 4<br />

Let σ = <br />

3<br />

4 1 6<br />

This can be seen as:<br />

5<br />

5<br />

6<br />

<br />

2<br />

1<br />

2<br />

5<br />

σ<br />

σ<br />

( { )( ( )}) ()( ( ) ( )( }{ ) )( ( )}) )( )}{ ( )}<br />

σS H A 1 =<br />

13 1 e,<br />

2123<br />

246<br />

S,<br />

13 , H<br />

5132<br />

2,<br />

= 2313<br />

e<br />

,,<br />

1123 13 246 2<br />

, H132<br />

3<br />

3=<br />

e,<br />

23<br />

2 1<br />

β [<br />

3<br />

3<br />

S=<br />

3<br />

: A3<br />

] = ,<br />

= αβ 2,<br />

= ,<br />

α β = <br />

1<br />

3 A 23<br />

2<br />

1 3<br />

3<br />

2<br />

2<br />

3<br />

,<br />

1<br />

σ<br />

6<br />

4<br />

In cycle notation σ can be written as<br />

Therefore from example 6:<br />

It has 4 proper subgroups:<br />

and<br />

so A 3<br />

is a subgroup of S 3<br />

of index 2. It can be easily verified that A3 ∆ S3<br />

. Infact, it can<br />

be generalised, that every subgroup of index 2 is a normal subgroup in its parent group.<br />

group.<br />

is called alternating

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