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Advanced Abstract Algebra - Maharshi Dayanand University, Rohtak

Advanced Abstract Algebra - Maharshi Dayanand University, Rohtak

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78<br />

ADVANCED ABSTRACT ALGEBRA<br />

An element<br />

In<br />

such that ab = 0 for some<br />

is a divisor of zero.<br />

in R, is called a divisor of zero.<br />

In<br />

are divisors of zero.<br />

2. Let IR be the set of real numbers, and<br />

is acommutative ring wth identity. + : defined by<br />

(Addition and multiplication are defined pointwise).<br />

Ibg= x ∀x ∈1 R, I is identity of the ring R.<br />

Note that (R, +, .) is a commutative ring with identity and also with divisors of zero.<br />

If<br />

R bg= S<br />

f x<br />

and g x<br />

x <<br />

T 0 , 0<br />

1 , x ≥ 0<br />

R bg= S<br />

x <<br />

T 1 , 0<br />

0 , x ≥ 0<br />

b gbg bgbg<br />

fbgbg<br />

x I x x IR<br />

x x IR<br />

fbg 1<br />

x x IR<br />

b.<br />

gbg bgbg bg<br />

bg 0 bg 0<br />

then f . g x = f x g x = 0 ∀x ∈1R.<br />

In above example, (f.I) (x)<br />

= ∀ ∈<br />

= ∀ ∈<br />

= ∀ ∈<br />

If f g x = f x g x = I x = 1 ∀ x ∈IR<br />

and f x ≠ , g x ≠ ∀ x∈<br />

R, then f has a multiplicative inverse ⇔<br />

bg= +<br />

f x<br />

. Hence for example<br />

bg=<br />

2 sin x has a multiplicative inverse, but g x Sin x does not.<br />

Definition: Integral Domain:<br />

If bR +,. gis a commutative ring with identity such that for all<br />

Examples:<br />

1. Z 6<br />

, + , . gis not an integral domain.<br />

2.<br />

b<br />

Integral domain.<br />

Definition:<br />

the ring of real valued functions, the example given on page 5 is not an<br />

A non-commutative ring with identity is a skew field (or Division ring) if every non-zero element has its<br />

inverse in it.<br />

Zb<br />

b<br />

ba<br />

a,<br />

Rf<br />

f≠<br />

bf

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