Advanced Abstract Algebra - Maharshi Dayanand University, Rohtak
Advanced Abstract Algebra - Maharshi Dayanand University, Rohtak
Advanced Abstract Algebra - Maharshi Dayanand University, Rohtak
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UNIT-I<br />
15<br />
Definition: Group Homomorphism<br />
Let be a mapping from a group G to a group defined by<br />
: G<br />
a<br />
bg bgbg<br />
f ab = f a f b ∀a, b ∈G.<br />
f is called homomorphism of groups.<br />
Definition: Kernel of a Homomorphism<br />
Let : G<br />
be a group homomorphism and be the identify of<br />
denoted by Ker is defined by<br />
. Then Kernel of<br />
Ker<br />
=<br />
G<br />
homomorphism<br />
Ker<br />
We note that ker G. (It is easy to show that ker f is a subgroup of G)<br />
Θm<br />
g f∆<br />
−<br />
xbg∀ a Ga : ∈ f Gbg<br />
x,<br />
Satisfying<br />
1 ker b g<br />
⊆ ker<br />
−1 f g f f∀ gx ∈<br />
G<br />
−<br />
g f g ef g x f<br />
We show that<br />
= 1<br />
Ge<br />
x<br />
fd G,<br />
−1<br />
∈( g xgf<br />
() ix<br />
= ) e = ∀d xf<br />
∈( xi ker ) ( bgbg Θf<br />
f,<br />
( x)<br />
∈Gdand<br />
ie<br />
isbg, the identify Θ ∈ kerof<br />
G )<br />
Let x be any element of ker<br />
.<br />
Then<br />
−1 −1<br />
d i bg d i b<br />
f g f g = f g g Θ f ishomomorphism<br />
bg<br />
= f e<br />
= e<br />
( Any homomorphism of groups carries identity of G to identity of<br />
Explanation:<br />
g<br />
)<br />
=<br />
=<br />
f<br />
f<br />
( xe)<br />
( x) f ( e) in G<br />
So by cancellation property in<br />
, we have<br />
=<br />
(e).)<br />
Hence<br />
g −1<br />
xg ∈ ker f ∀g<br />
∈G,<br />
∀ x ∈ker<br />
f ker f∆G