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Advanced Abstract Algebra - Maharshi Dayanand University, Rohtak

Advanced Abstract Algebra - Maharshi Dayanand University, Rohtak

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UNIT-I<br />

15<br />

Definition: Group Homomorphism<br />

Let be a mapping from a group G to a group defined by<br />

: G<br />

a<br />

bg bgbg<br />

f ab = f a f b ∀a, b ∈G.<br />

f is called homomorphism of groups.<br />

Definition: Kernel of a Homomorphism<br />

Let : G<br />

be a group homomorphism and be the identify of<br />

denoted by Ker is defined by<br />

. Then Kernel of<br />

Ker<br />

=<br />

G<br />

homomorphism<br />

Ker<br />

We note that ker G. (It is easy to show that ker f is a subgroup of G)<br />

Θm<br />

g f∆<br />

−<br />

xbg∀ a Ga : ∈ f Gbg<br />

x,<br />

Satisfying<br />

1 ker b g<br />

⊆ ker<br />

−1 f g f f∀ gx ∈<br />

G<br />

−<br />

g f g ef g x f<br />

We show that<br />

= 1<br />

Ge<br />

x<br />

fd G,<br />

−1<br />

∈( g xgf<br />

() ix<br />

= ) e = ∀d xf<br />

∈( xi ker ) ( bgbg Θf<br />

f,<br />

( x)<br />

∈Gdand<br />

ie<br />

isbg, the identify Θ ∈ kerof<br />

G )<br />

Let x be any element of ker<br />

.<br />

Then<br />

−1 −1<br />

d i bg d i b<br />

f g f g = f g g Θ f ishomomorphism<br />

bg<br />

= f e<br />

= e<br />

( Any homomorphism of groups carries identity of G to identity of<br />

Explanation:<br />

g<br />

)<br />

=<br />

=<br />

f<br />

f<br />

( xe)<br />

( x) f ( e) in G<br />

So by cancellation property in<br />

, we have<br />

=<br />

(e).)<br />

Hence<br />

g −1<br />

xg ∈ ker f ∀g<br />

∈G,<br />

∀ x ∈ker<br />

f ker f∆G

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