Advanced Abstract Algebra - Maharshi Dayanand University, Rohtak
Advanced Abstract Algebra - Maharshi Dayanand University, Rohtak
Advanced Abstract Algebra - Maharshi Dayanand University, Rohtak
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80<br />
ADVANCED ABSTRACT ALGEBRA<br />
xy = 0 ⇒ xyy− 1 = 0. y− 1<br />
⇒ x.e = 0<br />
⇒ x = 0<br />
Hence xy = 0 ⇒ x = 0 or y = 0 and so F is without zero divisor.<br />
Remark. It follows from this theorem that every field is an integral domain. But the converse is not true.<br />
For example, ring of integers is an integral domain but it is not a field.<br />
Theorem:<br />
Any finite integral domain is a field.<br />
Proof:<br />
Let D be a finite integral domain<br />
let D * = D - (o).<br />
Since cancellation law holds in integral domain D. Since D is finite set, so one-to-one function<br />
set to itself must be onto, so f is onto. Hence<br />
from finite<br />
*<br />
∃ a ∈ D such that f a =<br />
*<br />
i. e. da = 1,<br />
a ∈D CD<br />
bg 1.<br />
le Df<br />
Kf<br />
ψ<br />
and so d is invertible. Hence every non-zero element in D is invertible, i.e. D is a field.<br />
Remark:<br />
Does there exist an integral domain of 6 elements No, we shall explain in Unit V that every finite integral<br />
domain must be p n , for some prime p, every + ve integar n.<br />
Ring homomorphism:<br />
Let R and S be rings. A function<br />
ψ : R<br />
⎯⎯⎯<br />
→ S<br />
is called ring homomosphism<br />
b g bg bgand<br />
if ψ a + b = ψ a + ψ b<br />
for all<br />
a, b∈R.<br />
Kernel of ring homomorphism:<br />
is called the zero elements of S.<br />
, the kernel of<br />
, denoted by ker<br />
.