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Advanced Abstract Algebra - Maharshi Dayanand University, Rohtak

Advanced Abstract Algebra - Maharshi Dayanand University, Rohtak

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80<br />

ADVANCED ABSTRACT ALGEBRA<br />

xy = 0 ⇒ xyy− 1 = 0. y− 1<br />

⇒ x.e = 0<br />

⇒ x = 0<br />

Hence xy = 0 ⇒ x = 0 or y = 0 and so F is without zero divisor.<br />

Remark. It follows from this theorem that every field is an integral domain. But the converse is not true.<br />

For example, ring of integers is an integral domain but it is not a field.<br />

Theorem:<br />

Any finite integral domain is a field.<br />

Proof:<br />

Let D be a finite integral domain<br />

let D * = D - (o).<br />

Since cancellation law holds in integral domain D. Since D is finite set, so one-to-one function<br />

set to itself must be onto, so f is onto. Hence<br />

from finite<br />

*<br />

∃ a ∈ D such that f a =<br />

*<br />

i. e. da = 1,<br />

a ∈D CD<br />

bg 1.<br />

le Df<br />

Kf<br />

ψ<br />

and so d is invertible. Hence every non-zero element in D is invertible, i.e. D is a field.<br />

Remark:<br />

Does there exist an integral domain of 6 elements No, we shall explain in Unit V that every finite integral<br />

domain must be p n , for some prime p, every + ve integar n.<br />

Ring homomorphism:<br />

Let R and S be rings. A function<br />

ψ : R<br />

⎯⎯⎯<br />

→ S<br />

is called ring homomosphism<br />

b g bg bgand<br />

if ψ a + b = ψ a + ψ b<br />

for all<br />

a, b∈R.<br />

Kernel of ring homomorphism:<br />

is called the zero elements of S.<br />

, the kernel of<br />

, denoted by ker<br />

.

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