Advanced Abstract Algebra - Maharshi Dayanand University, Rohtak
Advanced Abstract Algebra - Maharshi Dayanand University, Rohtak
Advanced Abstract Algebra - Maharshi Dayanand University, Rohtak
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UNIT-II<br />
61<br />
of nilpotency of G) , so Z c<br />
(G) = G. Now G'(<br />
. So we get the derived series<br />
.<br />
Hence G is solvable.<br />
Note that the converse is not true i.e. a solvable group need not be nilpotent. For example :<br />
G ∆A<br />
∆bg<br />
3 3 1<br />
S 3<br />
is solvable but is not nilpolent because center of S 3<br />
is (1). (Every nilpotent group has a non-trivial center)<br />
Exmple 13 :<br />
Consider<br />
b g bg b g bg<br />
. Now Z Z × S = Z × 1 and every Z × S = Z × 1 . Therefore, ascending<br />
1 2 3 2<br />
Z k 2 3 2<br />
central series (or upper central series) never reach G. Hence Z<br />
× S is not niloptent.<br />
2 3<br />
( )<br />
l q l1q<br />
c<br />
Zc−G1 , GG' cZe<br />
2 , − G,<br />
c −1<br />
G = ∆ Z b g (<br />
' ∆ ' ∆ ∆ ∆=<br />
1<br />
c )<br />
2<br />
× S3<br />
− − − G =