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Gene Cloning

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362 <strong>Gene</strong> <strong>Cloning</strong><br />

Q11.3. Why is it essential to remove all DNA from the RNA sample before<br />

northern analysis?<br />

A11.3. The labeled probe used to detect the RNA during northern analysis<br />

will also hybridize to any contaminating DNA as all genes, expressed or otherwise,<br />

will be present in the genomic DNA; this can give you a false positive<br />

for transcription of the gene.<br />

Q11.4. The QRT–PCR protocol utilizes random hexanucleotide primers to<br />

generate the cDNA prior to QRT–PCR. What is the advantage of using random<br />

hexanucleotides rather that a gene-specific primer?<br />

A11.4. Random hexanucleotides will generate a population of cDNAs<br />

reflecting the range of RNA molecules in the starting sample. It is therefore<br />

possible to subsequently use quantitative real-time PCR on the same mixture<br />

of cDNAs to determine the levels of mRNA for any gene for which the DNA<br />

sequence is known.<br />

Q11.5. Which technique, standard northern or reverse northern analysis<br />

would be best to study (a) the levels of mRNA for the same gene in several<br />

RNA samples (e.g. from different cell types) or (b) the levels of mRNA for<br />

several genes in the same RNA sample?<br />

A11.5. (a) Standard northern analysis is best suited to determining the<br />

mRNA levels for the same gene from several samples, because each RNA sample<br />

can be immobilized on the same membrane and the same labeled probe<br />

hybridized and the level of hybridization quantified. You cannot use two different<br />

probes in the same hybridization, so cannot analyze more than one<br />

gene at a time.<br />

(b) Reverse northern would be best for determining the mRNA levels of several<br />

genes within the same sample because the probes are immobilized on<br />

the membrane, so several probes can be immobilized on the same membrane.<br />

The labeled cDNA will then hybridize to the immobilized probe and<br />

the level of hybridization of each mRNA can be quantified.<br />

Q11.6. Figure 11.15b shows how a series of overlapping fragments can be<br />

used to map where a transcription factor binds within a large DNA fragment.<br />

Why would you use overlapping fragments rather than a series of<br />

non-overlapping fragments?<br />

A11.6. If you used a series of non-overlapping fragments, the DNA binding<br />

site may be spilt between two adjacent fragments and therefore no binding<br />

would be detected. For example, if you have two fragments 1–40 and 40–80,<br />

the protein may require sequences from 35 to 50 to bind, and so would bind<br />

neither fragment. Overlapping fragments are used to ensure that any potential<br />

site is present on at least one fragment. For example, if you have three<br />

fragments 1–40, 20–60 and 40–80, a protein that binds from 35 to 50 could<br />

bind to the 20–60 fragment.

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