Gilson and Voss - Voss Associates
Gilson and Voss - Voss Associates
Gilson and Voss - Voss Associates
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Activity in DPM vs Particle Size in microns<br />
for oxide form of various isotopes<br />
0.5ì 1ì 5ì 10ì 50ì<br />
234<br />
U 8.7E-3 0.07 9 69.7 8700<br />
235<br />
U 3.0E-6 2.4E-5 3E-3 0.02 3<br />
238<br />
U 4.7E-7 3.8E-6 5E-4 3.8E-3 0.47<br />
237<br />
Np 1.0E-3 8.0E-3 1.0 8 1000<br />
238<br />
Pu 25 201 2.5E4 2E5 2.5E7<br />
239<br />
Pu 0.09 0.73 91 730 9.1E4<br />
240<br />
Pu 0.33 2.7 333 2670 3.3E5<br />
241<br />
Pu 151 1210 1.5E5 1.2E6 1.5E8<br />
241<br />
Am 5.1 41.1 5140 4.1E4 5.14E6<br />
Calculating Activity vs Particle Size<br />
3<br />
1. Volume of the particle is V = 1/6ðd .<br />
2. Use the density of the isotope listed in this reference.<br />
3. Mass of the particle is M = V x density.<br />
4. Activity of the particle is A = M x specific activity.<br />
Correct the activity of the particle for the oxide form if you need<br />
238<br />
that; the molecular weight of Pu is 238, the activity of the<br />
dioxide form must be reduced by the ratio of the molecular<br />
238<br />
weight of the dioxide form to the molecular weight of Pu .<br />
Multiply the calculated activity by 238/270 to get the activity of<br />
the dioxide form.<br />
For particles larger than about 1ì the aerodynamic diameter is<br />
approximately equal to the physical diameter times the square<br />
root of the density. The 10ì diameter particle in our example<br />
would have an equivalent aerodynamic diameter of 34ì (10ì x<br />
the square root of 11.46). This must be taken into account in air<br />
sampling/monitoring situations.<br />
Activity in DPM vs Particle Size in microns<br />
for oxide form of various isotopes<br />
0.5ì 1ì 5ì 10ì 50ì<br />
234<br />
U 8.7E-3 0.07 9 69.7 8700<br />
235<br />
U 3.0E-6 2.4E-5 3E-3 0.02 3<br />
238<br />
U 4.7E-7 3.8E-6 5E-4 3.8E-3 0.47<br />
237<br />
Np 1.0E-3 8.0E-3 1.0 8 1000<br />
238<br />
Pu 25 201 2.5E4 2E5 2.5E7<br />
239<br />
Pu 0.09 0.73 91 730 9.1E4<br />
240<br />
Pu 0.33 2.7 333 2670 3.3E5<br />
241<br />
Pu 151 1210 1.5E5 1.2E6 1.5E8<br />
241<br />
Am 5.1 41.1 5140 4.1E4 5.14E6<br />
Calculating Activity vs Particle Size<br />
3<br />
1. Volume of the particle is V = 1/6ðd .<br />
2. Use the density of the isotope listed in this reference.<br />
3. Mass of the particle is M = V x density.<br />
4. Activity of the particle is A = M x specific activity.<br />
Correct the activity of the particle for the oxide form if you need<br />
238<br />
that; the molecular weight of Pu is 238, the activity of the<br />
dioxide form must be reduced by the ratio of the molecular<br />
238<br />
weight of the dioxide form to the molecular weight of Pu .<br />
Multiply the calculated activity by 238/270 to get the activity of<br />
the dioxide form.<br />
For particles larger than about 1ì the aerodynamic diameter is<br />
approximately equal to the physical diameter times the square<br />
root of the density. The 10ì diameter particle in our example<br />
would have an equivalent aerodynamic diameter of 34ì (10ì x<br />
the square root of 11.46). This must be taken into account in air<br />
sampling/monitoring situations.<br />
Page 46<br />
Page 46<br />
Activity in DPM vs Particle Size in microns<br />
for oxide form of various isotopes<br />
0.5ì 1ì 5ì 10ì 50ì<br />
234<br />
U 8.7E-3 0.07 9 69.7 8700<br />
235<br />
U 3.0E-6 2.4E-5 3E-3 0.02 3<br />
238<br />
U 4.7E-7 3.8E-6 5E-4 3.8E-3 0.47<br />
237<br />
Np 1.0E-3 8.0E-3 1.0 8 1000<br />
238<br />
Pu 25 201 2.5E4 2E5 2.5E7<br />
239<br />
Pu 0.09 0.73 91 730 9.1E4<br />
240<br />
Pu 0.33 2.7 333 2670 3.3E5<br />
241<br />
Pu 151 1210 1.5E5 1.2E6 1.5E8<br />
241<br />
Am 5.1 41.1 5140 4.1E4 5.14E6<br />
Calculating Activity vs Particle Size<br />
3<br />
1. Volume of the particle is V = 1/6ðd .<br />
2. Use the density of the isotope listed in this reference.<br />
3. Mass of the particle is M = V x density.<br />
4. Activity of the particle is A = M x specific activity.<br />
Correct the activity of the particle for the oxide form if you need<br />
238<br />
that; the molecular weight of Pu is 238, the activity of the<br />
dioxide form must be reduced by the ratio of the molecular<br />
238<br />
weight of the dioxide form to the molecular weight of Pu .<br />
Multiply the calculated activity by 238/270 to get the activity of<br />
the dioxide form.<br />
For particles larger than about 1ì the aerodynamic diameter is<br />
approximately equal to the physical diameter times the square<br />
root of the density. The 10ì diameter particle in our example<br />
would have an equivalent aerodynamic diameter of 34ì (10ì x<br />
the square root of 11.46). This must be taken into account in air<br />
sampling/monitoring situations.<br />
Activity in DPM vs Particle Size in microns<br />
for oxide form of various isotopes<br />
0.5ì 1ì 5ì 10ì 50ì<br />
234<br />
U 8.7E-3 0.07 9 69.7 8700<br />
235<br />
U 3.0E-6 2.4E-5 3E-3 0.02 3<br />
238<br />
U 4.7E-7 3.8E-6 5E-4 3.8E-3 0.47<br />
237<br />
Np 1.0E-3 8.0E-3 1.0 8 1000<br />
238<br />
Pu 25 201 2.5E4 2E5 2.5E7<br />
239<br />
Pu 0.09 0.73 91 730 9.1E4<br />
240<br />
Pu 0.33 2.7 333 2670 3.3E5<br />
241<br />
Pu 151 1210 1.5E5 1.2E6 1.5E8<br />
241<br />
Am 5.1 41.1 5140 4.1E4 5.14E6<br />
Calculating Activity vs Particle Size<br />
3<br />
1. Volume of the particle is V = 1/6ðd .<br />
2. Use the density of the isotope listed in this reference.<br />
3. Mass of the particle is M = V x density.<br />
4. Activity of the particle is A = M x specific activity.<br />
Correct the activity of the particle for the oxide form if you need<br />
238<br />
that; the molecular weight of Pu is 238, the activity of the<br />
dioxide form must be reduced by the ratio of the molecular<br />
238<br />
weight of the dioxide form to the molecular weight of Pu .<br />
Multiply the calculated activity by 238/270 to get the activity of<br />
the dioxide form.<br />
For particles larger than about 1ì the aerodynamic diameter is<br />
approximately equal to the physical diameter times the square<br />
root of the density. The 10ì diameter particle in our example<br />
would have an equivalent aerodynamic diameter of 34ì (10ì x<br />
the square root of 11.46). This must be taken into account in air<br />
sampling/monitoring situations.<br />
Page 46<br />
Page 46