Cartridge and block spindles - Gilman USA

ApplicationexamplesThe following application examples will help familiarize you with thecharts and formulas required to determine correct spindle selection.Application example #1• Boring 1 7/8” diameter hole in die cast aluminum• Rough size 1 5/8”• Carbide inserts, 5” tool overhang from front of housingStep 1Determine the peripheral speed of tool (FPM), feed rate of tool(lPR) and Unit Power Factor (P) from the chart under Boring,Aluminum Die Casting and Carbide Tooling.Results: 475 FPM, .020 IPR and .3 HP/in. 3 /min.Step 2Determine the depth of cut.Results: 1.88 -1.62 = .13 in.2Step 3Calculate the required horsepower using the Boring HP formula.Results: Boring HP = 12 x 475 FPM x .020 IPR x .13 in. x.3 HP/in. 3 /min.Boring HP = 4.45Step 4Calculate the speed and torque required.Results: RPM = 3.82 x 475 FPM1.88 in.RPM = 965Torque = 4.45 HP x 63025965 RPMTorque = 291 in.-lbs.Step 5Compare the tool overhang, hole diameter and torque to valueson Spindle Specification Charts and follow the sizing rules onpage 5.Results: 4000 SpindleFront bearing bore 55mm > 1.88 in. (48mm)Maximum tool overhang 5 1/8 > 5 in.Maximum torque 1000 in.-lbs. > 291 in.-lbs.3500 SpindleFront bearing bore 45mm < 1.88 in. (48mm)Maximum tool overhang 3 7/8 < 5 in. maximumtorque 527 in.-lbs. > 291 in.-lbs.By comparing the results, model 4000C-X1 M-BR would be thespindle of choice.Application example #2• Face mill a 2 1/2” wide, 1/8” deep pad in 225 BHN steel witha 4” diameter 6-tooth carbide insert cutterStep 1Determine the peripheral speed of tool (FPM), feed rate of tool(lPT) and Unit Power Factor (P) from the chart under Milling,Steel Medium 200-325 BHN and Carbide Tooling.Results: 200 FPM, .006 IPT and 1.8 HP/in. 3 /min.Step 2Calculate the speed of tool in RPMResults: RPM = 3.82 x 200 ft./min.4 in.RPM = 191Step 3Calculate the feed rate of tool in in./min. (IPM)Results: IPM = 191 rev./min. x 6 teeth x .006 in./toothIPM = 6.88Step 4Calculate the required horsepower using the Milling HP formula.Results: Milling HP = .12 in. x 2.5 in. x 6.881PM x1.8 HP/in. 3 /min.Milling HP = 3.72Step 5Calculate the torque requirements.Results: Torque = 3.72 HP x 63025191 RPMTorque = 1228 in.-lbs.Step 6Compare the speed and torque to the values on the SpindleSpecification Charts and follow the sizing rules on page 5.Results: 4000 SpindleMaximum torque 1000 in.-lbs.5500 SpindleMaximum torque 2164 in.-lbs.By comparing the results, model 5500B-X3M-40 would be thespindle of choice.50 ©2011 Gilman USA, LLC