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Statistical models of elasticity in main chain and smectic liquid ...

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2.C. COUNTING CONFIGURATIONS BY INDUCTION 43hairp<strong>in</strong>s use up a negligible amount <strong>of</strong> the end-to-end distance) to meet theend-to-end distance constra<strong>in</strong>t. Similarly the second <strong>in</strong>equality is obta<strong>in</strong>edby consider<strong>in</strong>g the case when the added segment goes up a distance z ′ <strong>and</strong>the exist<strong>in</strong>g segment must then come down a distance z −z ′ . Then the twoquantities must be added with the correct sign to obta<strong>in</strong> the arc length whichmust be less that the total available arc length. Thus Eq. (2.124) can beevaluated as follows: first we assert the form <strong>of</strong> G n+ (z,N)G n+ (z,N) =1n(n−2)!! 2(N +z)n 2(N −z) n−22 . (2.129)Then use this, together with the previous result that G 0− (z,N) = δ(z +N)to obta<strong>in</strong>∫ ∫G (n+1)+ (z,N) = dz ′ dN ′ 1n(n−2)!! 2(N −N′ +z −z ′ ) n 2× (N −N ′ −z +z ′ ) n−22 δ(z ′ +N ′ )==∫ 0z−N2dz ′ 1n(n−2)!! 2(N +z)n 2 (N +2z ′ −z) n−221n!! 2(N2 −z 2 ) n 2 (2.130)Another defect can be added on <strong>in</strong> a similar way us<strong>in</strong>g the G that we havejust derived∫ ∫G (n+2)+ (z,N) = dz ′ dN ′ 1n!! 2(N −N′ −z +z ′ ) n 2× (N −N ′ +z −z ′ ) n 2 δ(z ′ −N ′ )==∫ z+N2dz ′ 10 n!! 2(N −z)n 2 (N −2z ′ +z) n 21+z)n+2 2(n+2)(n)!! 2(N (N −z) n 2 (2.131)This is now the orig<strong>in</strong>al form for the G n+ (z,N) so if it is true for n then it isalso true for n +2. A similar analysis can be carried out for the G n+ (z,N)(Fig. 2.14 a))which goes through <strong>in</strong> the same way, except with z → −z. Thuson comb<strong>in</strong><strong>in</strong>g the two results for the even caseG n+ (z,N) =1n(n−2)!! 2(N 2(N +z)n −z) n−22G n− (z,N) =1n−2n(n−2)!! 2(N −z)n 2 (N +z) 2G n (z,N) = G n− (z,N)+G n+ (z,N)=2n(n−2)!! 2N(N2 −z 2 ) n−22 (2.132)

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