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Statistical models of elasticity in main chain and smectic liquid ...

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64 CHAPTER 3. POLARISATION OF CHIRAL ELASTOMERSvector quantities at the first stage <strong>of</strong> cross-l<strong>in</strong>k<strong>in</strong>g. The fact that a n <strong>and</strong> r n0deform aff<strong>in</strong>ely can be used to express z as followsz = λ·λ −1f zf −tλ·λ −1f cf +tc. (3.37)This expression can then be substituted <strong>in</strong>to the expression for the free energy<strong>and</strong> the variables r n0 , z f , <strong>and</strong> c f quench-averaged over, whilst anneal<strong>in</strong>g overc. The required averages <strong>of</strong> the distribution are denoted as follows〈z f z f 〉 = 1 3 j(n−j)a2 n l f (3.38)〈r o n0 ro n0 〉 = 1 3 na2 l 0 (3.39)〈c f c f 〉 = 1 3 Cf . (3.40)These averages are used to evaluate the expression∫ ∫ ∫ [∫f elk B T = − dc f P(c f ) dr n0 P(r n0 ) dz f P(z f )ln]dce − Fk B T. (3.41)S<strong>in</strong>ce the rigid-rod cross-l<strong>in</strong>k is short compared to the span <strong>of</strong> a Gaussiancha<strong>in</strong> then the small elastic contribution <strong>of</strong> the rigid rod to the free energy isneglected. Terms l<strong>in</strong>ear <strong>in</strong> c f average to zero, terms <strong>in</strong> c <strong>and</strong> c f are small, <strong>and</strong>terms <strong>in</strong> c <strong>and</strong> z f are exp<strong>and</strong>ed down from the exponential <strong>and</strong> then averagedover w.r.t c <strong>and</strong> the result<strong>in</strong>g logarithmic term exp<strong>and</strong>ed.After evaluat<strong>in</strong>g these <strong>in</strong>tegrals the second stage <strong>of</strong> the cross-l<strong>in</strong>k<strong>in</strong>g occursat a r<strong>and</strong>om po<strong>in</strong>t along the polymer cha<strong>in</strong>, <strong>and</strong> consequently the r<strong>and</strong>omlychosen j is averaged over. The expression for the free energy density obta<strong>in</strong>edis given byf el = 1 ( [2 n sk B T Tr λ·A·λ T ·l −1] −Tr[λ·B ·λ T ·l ∗−1])l ∗ = l·C −1 ·lA = (1−α)l 0 +αλ −1f·l f ·λ −Tf+αdλ −1f·C f ·λ −TfB = αdλ −1f·l f ·λ −TfHere α = n rigid /(n 1 + n rigid ) where n rigid is the number density <strong>of</strong> secondstage cross-l<strong>in</strong>ks <strong>and</strong> n 1 is the number density <strong>of</strong> first stage cross-l<strong>in</strong>ks. Thusα is the fraction <strong>of</strong> second stage cross-l<strong>in</strong>ks. The constant d arises from averag<strong>in</strong>gover the position j that the rod l<strong>in</strong>ker is bonded, <strong>and</strong> is given byd = [ 2ln(n−1)t 2] / [ (n−1)a 2] . After this second stage <strong>of</strong> cross-l<strong>in</strong>k<strong>in</strong>g, therubber then relaxes to the optimal deformation. The total relaxation <strong>of</strong> therubber from its first cross-l<strong>in</strong>k<strong>in</strong>g state to its current relaxed state is denotedby λ r . This relaxation is chosen so as to m<strong>in</strong>imise the free energy density.

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