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Statistical models of elasticity in main chain and smectic liquid ...

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72 CHAPTER 3. POLARISATION OF CHIRAL ELASTOMERSis⎛ ⎞λ xx 0 δλ = ⎝ 10λ zzλ xx0 ⎠ (3.59)0 0 λ zzwhere λ xz is denoted simply by δ <strong>and</strong> volume constra<strong>in</strong>t has been <strong>in</strong>cluded.The λ xz component has been suppressed on geometric grounds, s<strong>in</strong>ce a λ zxdeformation is be<strong>in</strong>gapplied byplates attached tothesample. Thefreeenergydensity <strong>of</strong> the mixture <strong>of</strong> cha<strong>in</strong>s is given by]f ss = 1 2[λ·l µTr 0 ·λ T ·l −1 +αδ (tr) ·λ T ·nn·λ , (3.60)where as usual α = 〈 1 r 〉 − 1〈r〉 <strong>and</strong> the l 0 <strong>and</strong> l −1 are <strong>in</strong> terms <strong>of</strong> 〈r〉. Theaverage value for the b<strong>in</strong>ary mixture <strong>of</strong> cha<strong>in</strong>s considered here is given by:〈r〉 = qr 1 +(1−q)r 2 , where q is the fraction <strong>of</strong> ma<strong>in</strong> cha<strong>in</strong>s <strong>of</strong> anisotropy r 1<strong>and</strong> 1−q is the fraction <strong>of</strong> side cha<strong>in</strong>s <strong>of</strong> anisotropy r 2 . On substitut<strong>in</strong>g <strong>in</strong>tothis formula the director orientations n 0 = (0,0,1) <strong>and</strong> n = (s<strong>in</strong>θ,0,cosθ),then the follow<strong>in</strong>g expression for the free energy density is obta<strong>in</strong>ed2f ssµ=1λ 2 xx λ2 zz+λ 2 zz(1+(r −1)s<strong>in</strong> 2 θ)+(rδ 2 +λ 2 xx)(1+( 1r −1 )s<strong>in</strong> 2 θ− (r −1)λ 2 zzδs<strong>in</strong>2θ +αλ 2 xxs<strong>in</strong> 2 θ (3.61)This free energy density is very similar to the case where the driv<strong>in</strong>g deformationis a stretch along the x axis <strong>and</strong> a shear is <strong>in</strong>duced as a result <strong>of</strong> therotation <strong>of</strong> the director. As a result it is possible to re-express some <strong>of</strong> theresults for the imposed stretch case to apply here. For the case where there isno semi-s<strong>of</strong>tness the follow<strong>in</strong>g solution is obta<strong>in</strong>ed{λ 2 xx = 1 2(r +1−δ 2 r)− √ }(r +1−δ 2 r) 2 −4r (3.62)λ yy = 1 (3.63)λ zz = 1/λ xx (3.64)s<strong>in</strong> 2 θ =rr −1λ 2 xx −1λ 2 . (3.65)xxThis is the solution up to the end <strong>of</strong> s<strong>of</strong>tness which occurs at δ cr = 1 − 1 √ r.After this po<strong>in</strong>t, m<strong>in</strong>imisation <strong>of</strong> the free energy density becomes very difficultanalytically. The solution also becomes rapidly <strong>in</strong>tractable when we have af<strong>in</strong>ite value <strong>of</strong> α. To calculate the size <strong>of</strong> the polarisation <strong>in</strong> these cases anumerical procedure was used to m<strong>in</strong>imise the free energy density. A simplexalgorithm provides a convenient <strong>and</strong> robust method for m<strong>in</strong>imisation <strong>of</strong> thefree energy density. Fig. 3.10 shows a plot <strong>of</strong> the relaxation <strong>of</strong> λ xx , λ yy <strong>and</strong>λ zz for an elastomer consist<strong>in</strong>g <strong>of</strong> only one type <strong>of</strong> cha<strong>in</strong>, <strong>and</strong> for an elastomermade <strong>of</strong> a mixture <strong>of</strong> two sorts <strong>of</strong> cha<strong>in</strong>s. Note that the pureelastomers, α = 0)

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